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svetoff [14.1K]
2 years ago
6

An instructor gives his class a set of 18 problems with the information that the next quiz will consist of a random selection of

9 of them. If a student has figured out how to do 13 of the problems, what is the probability the he or she will answer correctly
all 9 questions? =.0147
atleast 8 questions ?
Mathematics
1 answer:
Anna [14]2 years ago
7 0

Answer:

The probability the he or she will answer correctly is 1.5%

Step-by-step explanation:

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How do you simplify (25/a -a l) / (5+a)
andrey2020 [161]

Simplify the following:

(25/a - a l)/(a + 5)


Put each term in 25/a - a l over the common denominator a: 25/a - a l = 25/a - (a^2 l)/a:

(25/a - (a^2 l)/a)/(a + 5)

25/a - (a^2 l)/a = (25 - a^2 l)/a:

Answer: ((25 - a^2 l)/a)/(a + 5)

7 0
2 years ago
Meghan says the difference between the least amount of time it takes a student to say the alphabet and the greatest amount of th
kupik [55]

Answer:

67 eghan says the difference between the least amount of time it takes a student to say the alphabet and the greatest amount

Step-by-step explanation:

4 0
2 years ago
Which products result in a difference of squares? Select three options. A. (x minus y)(y minus x) B. (6 minus y)(6 minus y) C. (
solniwko [45]

Answer:

Step-by-step explanation:

Hello, please consider the following.

A. (x minus y)(y minus x)

  (x-y)(y-x)=-(x-y)(x-y)=-(x-y)^2

   This is not a difference of squares.

B. (6 minus y)(6 minus y)

   (6-y)(6-y)=(6-y)^2

   This is not a difference of squares.

C. (3 + x z)(negative 3 + x z)

   This is a difference of squares.

   \boxed{(3+xz)(-3+xz)=(xz+3)(xz-3)=(xz)^2-3^2}

D. (y squared minus x y)(y squared + x y)

   This is a difference of squares.

   \boxed{(y^2-xy)(y^2+xy)=(y^2)^2-(xy)^2}

E. (64 y squared + x squared)(negative x squared + 64 y squared)

   This is a difference of squares.

   \boxed{(64y^2+x^2)(-x^2+64y^2)=(64y^2+x^2)(64y^2-x^2)=(64y^2)^2-(x^2)^2}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

6 0
1 year ago
Read 2 more answers
An insurance company sells an auto insurance policy that covers losses incurred by a policyholder, subject to a deductible of 10
Marrrta [24]

Answer:

Option E - 1000

Step-by-step explanation:

Let X stand for actual losses incurred.

Given that X follows an exponential distribution with mean 300,

To find the 95-th percentile of all claims that exceed 100.

In other words,

0.95 = Pr (100 < x < p95 ) / P(X > 100)

        = Fx( P95) − Fx(100 ) / 1− Fx (100)

, where Fx is the cumulative distribution function of X

since,  Fx(x) = 1 - e^ (-x/300)

0.95 = 1 - e^ (-P95/300) - [ 1 - e^ ( -100/300) ] / 1 -  [ 1 - e^ ( -100/300) ]

         = e^ ( -1/3 ) - e^ ( - P95//300) / e^(-1/3)

           = 1 - e^1/3 e^ (-P95/300)

The solution is given by , e^ ( - P95/300) = 0.05e^(-1/3)

P95 = -300 ln ( 0.05e^(-1/3) )

       = 999

       = 1000

8 0
2 years ago
The cost for a different taxi company is expressed with the equation y = 1.65x + 2.35, where x represents the miles driven and y
Rudiy27
To solve this, all you have to do is plug in the 14 where the x value is:
y=1.65(14) +2.35 which equals 25.45
9 0
2 years ago
Read 2 more answers
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