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Verdich [7]
2 years ago
7

PLZ ASAP MARK BRAINILEST Josiah conducts an experiment that has 4 possible outcomes. Sally conducts an experiment that has 10 po

ssible outcomes. The students conduct 50 trials each. Which statement best compares the two experiments?
Josiah’s results are more likely to be close to the predicted results because he had a smaller number of possible outcomes.
Sally’s results are more likely to be close to the predicted results because she had a larger number of possible outcomes.
Josiah and Sally have the same likelihood of the experimental results being close to the predicted results because they used the same number of trials.
Josiah and Sally have the same likelihood of the experimental results being close to the predicted results because the outcome of either experiment is unrelated to the outcome of the other experiment.
Mathematics
2 answers:
expeople1 [14]2 years ago
8 0

Answer:

Its A

Step-by-step explanation:

Rina8888 [55]2 years ago
3 0

Answer:Josiah's results are more likely to be close to the predicted results because he had a smaller number of possible outcomes.

Step-by-step explanation:

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A report states the average selling price is almost $520,000. Which measure of center was most likely used for the report?
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Answer:

Mean

Step-by-step explanation:

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N a circle with a radius of 2.8 cm, an arc is intercepted by a central angle of π5 radians. what is the arc length? use 3.14 for
Vilka [71]
By definition, the arc length is given by:
 arc = (theta) * (R)
 Where,
 theta: central angle
 R: radius
 Substituting values we have:
 arc = (π / 5) * (2.8)
 Rewriting we have:
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 Round to the hundredth:
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 Answer:
 
the arc length is:
 
arc = 1.76 cm
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Two objects are moving along separate linear paths where each path is described by position, d, and time, t. The variable d is m
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An artist is creating a sculpture using bendable metal rods of equal length. One rod is formed into the shape of a square and an
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Check the picture below.

so notice, their perimeter is the same, because the perimeter is just one rod anyway, and all rods are the same length, thus

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The data below shows the heights in inches of 10 students in a class. StudentHeight, in inches Student 153 Student 252.5 Student
Marianna [84]

Question not correct, so i have attached the correct question.

Answer:

SE = 0.59

Step-by-step explanation:

The mean of the students height is;

x' = (53 + 52.5 + 54 + 51 + 50.5 + 49.5 + 48 + 53 + 52 + 50)/10

x' = 51.35

Now, deviation from the mean for each height;

53 - 51.35 = 1.65

52.5 - 51.35 = 1.15

54 - 51.35 = 2.65

51 - 51.35 = -0.35

50.5 - 51.35 = -0.85

49.5 - 51.35 = -1.85

48 - 51.35 = -3.35

53 - 51.35 = 1.65

52 - 51.35 = 0.65

50 - 51.35 = -1.35

Now, square of the deviations above;

1.65² = 2.7225

1.15² = 1.3225

2.65² = 7.0225

-0.35² = 0.1225

-0.85² = 0.7225

-1.85² = 3.4225

-3.35² = 11.2225

1.65² = 2.7225

0.65² = 0.4225

-1.35² = 1.8225

Sum of the squared deviations;

2.7225 + 1.3225 + 7.0225 + 0.1225 + 0.7225 + 3.4225 + 11.2225 + 2.7225 + 0.4225 + 1.8225 = 31.525

Let's divide the sum by the DF of n - 1 i.e 10 - 1 = 9.

Thus;

31.525/9 = 3.50278

Taking the square root of that gives us the standard deviation.

Thus;

s = √3.50278

s = 1.8716

Formula for standard error is;

SE = s/√n

SE = 1.8716/√10

SE = 0.59

8 0
2 years ago
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