Students at a middle school were surveyed on how they get to school. Out of 230 students, 10% said they ride their bikes to scho
2 answers:
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Let
x--------> <span>the rectangle's length
y-------> </span><span>the rectangle's width
we now that
Area of rectangle=x*y
Area=256 cm</span>²
<span>256=x*y-------> equation 1
y=4x-48------> y=4x-48------> equation 2
substitute equation 2 in equation 1
256=x*[4x-48]-----> 256=4x</span>²-48x
4x²-48x-256=0
<span>
using a graph tool----> to resolve the second order equation
see the attached figure
the solution is
x=16 cm
y=4x-48----> y=4*16-48-----> y=16 cm
is a square
the answer is
</span>the rectangle's length is 16 cm
x--------> <span>the rectangle's length
y-------> </span><span>the rectangle's width
we now that
Area of rectangle=x*y
Area=256 cm</span>²
<span>256=x*y-------> equation 1
y=4x-48------> y=4x-48------> equation 2
substitute equation 2 in equation 1
256=x*[4x-48]-----> 256=4x</span>²-48x
4x²-48x-256=0
<span>
using a graph tool----> to resolve the second order equation
see the attached figure
the solution is
x=16 cm
y=4x-48----> y=4*16-48-----> y=16 cm
is a square
the answer is
</span>the rectangle's length is 16 cm
Answer:
Probability=
Step-by-step explanation:
As it is given that
Probability of toy A is defective is =P(A) =
Probability of toy b is defective if A is defective = P (B)=
WE have to find the P(A n B)
By the law of Probability
P(A n B) = P (A).P(B)
putting the values given to us
P(AnB)= *
Probability=
Draw a diagram to illustrate the problem as shown below.
The area of triangle acb is
A₁ = (1/2)*20*h = 10h
The area of trapezoid abcd is
A₂ = (1/2)*(20+12)*h = 16h
The ratio A₁/A₂ is
A₁/A₂ = (10h)/(16) = 5/8
Answer:
The ratio of triangle acb to the area of trapezoid abcd is 5/8.
The area of triangle acb is
A₁ = (1/2)*20*h = 10h
The area of trapezoid abcd is
A₂ = (1/2)*(20+12)*h = 16h
The ratio A₁/A₂ is
A₁/A₂ = (10h)/(16) = 5/8
Answer:
The ratio of triangle acb to the area of trapezoid abcd is 5/8.