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Oksi-84 [34.3K]
2 years ago
11

On Saturday, Craig rode his bike 5/8 of a mile. On Saturday, he rode his bike 1/2 of a mile. Craig added 5/8+1/2=6/10and plotted

6/10 on his number line.

Mathematics
1 answer:
VashaNatasha [74]2 years ago
3 0
* Craig's answer is not reasonable because to add fractions the denominators must be the same.

** Total distance = 5/8 + 1/2 = 5/8 + 4/8 = 9/8 miles

*** Using the line number to prove the answer:
The line number that represents the problem is in the attached figure.
while the distance between 0 and 1 divided to 8 sections
to represent (5/8) count 5 sections from zero ⇒⇒⇒ point (a)
and to represent (1/2) it is the midpoint between 0 and 1 which mean it is 4 sections but it will be counted from point (a) so, adding 4 sections to point (a) the result will be the point (b)
So, counting from 0 to point (b) will give us 9 sections
and while one section represents (1/8)
So the total distance will be 9 * (1/8) = 9/8 which is agree with the result obtained before

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Answer:

They are adjacent angles

Step-by-step explanation:

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2 years ago
If y varies directly as x, and y is 400 when x is r and y is r when x is 4, what is the numeric constant of variation in this
otez555 [7]

Answer:

10

Step-by-step explanation:

If there is a direct relation between two variables x and y then it can be represented as

y = kx ,

where y is dependent variable

x is  independent variable

k is constant of variation

_____________________________

First condition

y = 400

x = r

using y = kx then relationship will be

400 = kr

finding k here

k = 400/r

Second condition

y = r

x = 4

using y = kx then relationship will be

r = 4k

finding k

k = r/4

since  in both condition equation is same

thus, value of k will also be same

thus,

400/r = r/4

=> 400*4 = r*r

=> 1600 = r^2

\sqrt{r^{2} }  = \sqrt{1600} \\r = 40

Thus, 40 is the value of r

k = r/4 = 40/4 = 10

Thus, constant of variation is 10 which is correct choice.

To cross validate

k = 400/r = 400/40 = 10

7 0
1 year ago
Read 2 more answers
Z=25/5 what is the next step in the equation solving sequence.
lbvjy [14]

Answer:

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Z = 25/5

in simplest form........

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3 0
1 year ago
An airliner carries 150 passengers and has doors with a height of 78 in. Heights of men are normally distributed with a mean of
iogann1982 [59]

Answer:

Step-by-step explanation:

x, height of men is N(69, 2.8)

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Hence sample std dev = \frac{2.8}{\sqrt{150} } =0.229

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A) Prob that a random man from 150  can fit without bending

= P(X<78) = P(Z<3.214)=1.0000

B) n =75

Sample std dev = \frac{2.8}{\sqrt{75} } =0.3233

P(X bar <72) = P(Z<9.28) = 1.00

C) Prob of B is more relevent because average male passengers  would be more relevant than a single person

(D) The probability from part (b) is more relevant because it shows the proportion of flights where the mean height of the male passengers will be less than the door height.

3 0
1 year ago
Determine whether each of these sets is finite, countably infinite, or uncountable. For those that are countably in- finite, exh
mrs_skeptik [129]

Answer:

a) the negative integers set A is countably infinite.

   one-to-one correspondence with the set of positive integers:

   f: Z+ → A, f(n) = -n

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   one-to-one correspondence with the set of positive integers:

   f: Z+ → A, f(n) = 2n

c) the integers less than 100 set A is countably infinite.

   one-to-one correspondence with the set of positive integers:

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d) the real numbers between 0 and 12 set A is uncountable.

e) the positive integers less than 1,000,000,000 set A is finite.

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Step-by-step explanation:

A set is finite when its elements can be listed and this list has an end.  

A set is countably infinite when you can exhibit a one-to-one correspondence between the set of positive integers and that set.

A set is uncountable when it is not finite or countably infinite.

8 0
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