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elena-14-01-66 [18.8K]
2 years ago
5

Let C be the closed, piecewise smooth curve formed by traveling in straight lines between the points (-2,1), (-2,-3), (1,-1) , (

1,5), and back to (-2,1), in that order. Use Green's theorem to evaluate the integral:
Integral(C) (2xy) dx +(xy^2) dy
Mathematics
1 answer:
Greeley [361]2 years ago
6 0

The given points are the vertices of the quadrilateral

Q=\left\{(x,y)\mid-2\le x\le1,\dfrac{2x-5}3\le y\le\dfrac{4x+11}3\right\}

By Green's theorem, the line integral is

\displaystyle\int_C2xy\,\mathrm dx+xy^2\,\mathrm dy=\iint_Q\frac{\partial(xy^2)}{\partial x}-\frac{\partial(2xy)}{\partial y}\,\mathrm dA

=\displaystyle\int_{-2}^1\int_{(2x-5)/3}^{(4x+11)/3}y^2-2x\,\mathrm dy\,\mathrm dx=\boxed{61}

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You sell sporting goods. Your wages depend on the value of your sales. One week you sold $3,500 in sporting goods, earning $950.
Semmy [17]

Answer:

y = 0.2x + 250

Step-by-step explanation:

let the sales be x and y be earnings

thus,

given

x₁ = $3,500 ; y₁ = $950

and,

x₂ = $2,800 ; y₂ = $810

Now,

the standard line equation is given as:

y = mx + c

here,

m is the slope

c is the constant

also,

m = \frac{y_2-y_1}{x_2-x_1}

or

m = \frac{810-950}{\textup{2,800-3,500}}

or

m = 0.2

substituting the value of 'm' in the equation, we get

y = 0.2x + c

now,

substituting the x₁ = $3,500 and y₁ = $950 in the above equation, we get

$950 = 0.2 × $3,500 + c

or

$950 = $700 + c

or

c = $250

hence,

The equation comes out as:

y = 0.2x + 250

7 0
1 year ago
Kevin and Brittany write an equation to represent the following relationship, and both students solve their equation. Who found
Vadim26 [7]
Kevin, because the problem says the difference of a number (x) and 20, and since 20 is mentioned second, it would therefore be the second number in the problem
3 0
1 year ago
If a certain number is increased by 5 one half of the result is three-fifths of the excess of 61 over the number find the number
PSYCHO15rus [73]

Answer:

= 391/11

Let say number = N

a certain number is increased by 5

= N + 5

,one-half of the result

= (N + 5)/2

Three -fifths of the excess of 61 over the number.

= (3/5)(61 - N)

Equating both

(N + 5)/2  = (3/5)(61 - N)

multiplying by 10 both sides

=> 5(N + 5) = 6(61 - N)

=> 5N + 25 = 366 - 6N

=> 11N = 391

=> N = 391/11

Step-by-step explanation:

8 0
1 year ago
Dominic earns $285 per week plus an 8% commission rate on all his sales. If Dominic sells $4,213 worth of merchandise in one wee
nexus9112 [7]
(4213*.08)+285=
337.04+285=
622.04
3 0
1 year ago
The function f(t) = 4t2 − 8t + 8 shows the height from the ground f(t), in meters, of a roller coaster car at different times t.
lidiya [134]

Answer:

f(t) = 4(t − 1)2 + 4; the minimum height of the roller coaster is 4 meters from the ground

Step-by-step explanation:

The function is a quadratic where t is time and f(t) is the height from the ground in meters. You can write the function f(t) = 4t2 − 8t + 8 in vertex form by completing the square. Complete the square by removing a GCF from 4t2 - 8t. Take the middle term and divide it in two. Add its square. Remember to subtract the square as well to maintain equality.

f(t) = 4t2 − 8t + 8

f(t) = 4(t2 - 2t) + 8                                  The middle term is -2t

f(t) = 4(t2 - 2t + 1) + 8 - 4                        -2t/2 = -1; -1^2 = 1

f(t) = 4(t-1)^2 + 4                                      Add 1 and subtract 4 since 4*1 = 4.

The vertex (1,4) means at a minimum the roller coaster is 4 meters from the ground.

  • f(t) = 4(t − 1)2 + 2; the minimum height of the roller coaster is 2 meters from the ground
  • f(t) = 4(t − 1)2 + 2; the minimum height of the roller coaster is 4 meters from the ground
  • f(t) = 4(t − 1)2 + 4; the minimum height of the roller coaster is 1 meter from the ground
  • f(t) = 4(t − 1)2 + 4; the minimum height of the roller coaster is 4 meters from the ground
8 0
2 years ago
Read 2 more answers
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