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1 year ago

How much power is produced by a flashlight that has a voltage of 12 volts and a current of 6.5 × 10-2 amps?

Mathematics

2 answers:

mezya [45]1 year ago

4 0

Answer:

The power produced by the flashlight is 0.78 watts

Step-by-step explanation:

We are given that a flashlight has a voltage of 12 volts and a current of 6.5 × 10^-2 amps and we are to find its power.

We know the formula of power:

Power = I × V

where I is the current and V is the voltage.

Substituting the values in the above formula:

Power = $6.5$ × $10^-2$ × 12

Therefore, the power produced by the flashlight is 0.78 watts.

Jlenok [28]1 year ago

3 0

Answer:

0.78 Watts is correct answer.

Step-by-step explanation:

Formula:

P=V*I

=12*(6.5*10^-2)

= 12*0.065

=0.78 Watt.

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A baseball player has 39 hits in 134 times at bat. how many hits must he get in the next 46 times at bat to finish the year with

faust18 [17]

Answer:

He must get 33 hits in his next 46 times at bat to finish the year with a .400 batting average

Step-by-step explanation:

The player has already batted 134 times and will still bat 46 times. So in the end of the year, he is going to have 134 + 46 = 180 at bats.

How many hits does he need to have to hit .400?

This is 40% of 180, which is 0.4*180 = 72.

He has already 39 hits, so in his next 46 at bats, he will need 72 - 39 = 33 hits.

4 0

2 years ago

To test whether or not there is a difference between treatments A, B, and C, a sample of 12 observations has been randomly assig

Keith_Richards [23]

Answer:

1. Null hypothesis: $\mu_{A}=\mu_{B}=\mu_{C}$

Alternative hypothesis: Not all the means are equal $\mu_{i}\neq \mu_{j}, i,j=A,B,C$

2. D. 36

3. C. 34

4. B. 1.059

5. B. 8.02

Step-by-step explanation:

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"

Part 1

The hypothesis for this case are:

Null hypothesis: $\mu_{A}=\mu_{B}=\mu_{C}$

Alternative hypothesis: Not all the means are equal $\mu_{i}\neq \mu_{j}, i,j=A,B,C$

Part 2

In order to find the mean square between treatments (MSTR), we need to find first the sum of squares and the degrees of freedom.

If we assume that we have $p$ groups and on each group from $j=1,\dots,p$ we have $n_j$ individuals on each group we can define the following formulas of variation:

$SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2$

$SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2$

$SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2$

And we have this property

$SST=SS_{between}+SS_{within}$

We need to find the mean for each group first and the grand mean.

$\bar X =\frac{\sum_{i=1}^n x_i}{n}$

If we apply the before formula we can find the mean for each group

$\bar X_A = 27$ , $\bar X_B = 24$ , $\bar X_C = 30$ . And the grand mean $\bar X = 27$

Now we can find the sum of squares between:

$SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2$

Each group have a sample size of 4 so then $n_j =4$

$SS_{between}=SS_{model}=4(27-27)^2 +4(24-27)^2 +4(30-27)^2=72$

The degrees of freedom for the variation Between is given by $df_{between}=k-1=3-1=2$ , Where k the number of groups k=3.

Now we can find the mean square between treatments (MSTR) we just need to use this formula:

$MSTR=\frac{SS_{between}}{k-1}=\frac{72}{2}=36$

D. 36

Part 3

For the mean square within treatments value first we need to find the sum of squares within and the degrees of freedom.

$SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2$

$SS_{error}=(20-27)^2 +(30-27)^2 +(25-27)^2 +(33-27)^2 +(22-24)^2 +(26-24)^2 +(20-24)^2 +(28-24)^2 +(40-30)^2 +(30-30)^2 +(28-30)^2 +(22-30)^2 =306$

And the degrees of freedom are given by:

$df_{within}=N-k =3*4 -3 = 12-3=9$ . N represent the total number of individuals we have 3 groups each one with a size of 4 individuals. And k the number of groups k=3.

And now we can find the mean square within treatments:

$MSE=\frac{SS_{within}}{N-k}=\frac{306}{9}=34$

C. 34

Part 4

The test statistic F is given by this formula:

$F=\frac{MSTR}{MSE}=\frac{36}{34}=1.059$

B. 1.059

Part 5

The critical value is from a F distribution with degrees of freedom in the numerator of 2 and on the denominator of 9 such that we have 0.01 of the area in the distribution on the right.

And we can use excel to find this critical value with this function:

"=F.INV(1-0.01,2,9)"

And we will see that the critical value is $F_{crit}=8.02$

B. 8.02

5 0

2 years ago

Yolanda used a reconciliation worksheet provided by her bank. Line 5 should equal line 6 at the end of the reconciliation, but i

forsale [732]

Answer is 19.99 dollars

Explanation:

Let us draw the reconciliatin done by Yolanda linewise

Banking reconciliation Worksheet Amount of Mega

1) Closing balance $ 345 89

2) the sum of any outstanding deposits or credits. 0.00

3) Sum of 1 and 2 345.89

4. sum of any outstanding checks or debits. $ 37 51 5.

5) (3)-(4) $ 308 38

6) checkbook balance. $ 328 37

7) Difference (6)-(5) $ 19.99

SInce difference is exactly 19.99 dollars Yolanda should look for the amount 19.99 dollars to find a solution to the problem i.e. to see the reason for the difference between lines 5 and 6

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1 year ago

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A fruit basket contains oranges and grape fruits. One-third of the oranges and one-fourth of the grapefruits were spoiled. You t

den301095 [7]

So if 1/3 0f the oranges equals 4, than you times it by three to get 3/3, so there were 12 oranges and 28 grapefruits, so the answer is 40

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2 years ago

The equation d = can be used to calculate the density, d, of an object with mass, m, and volume, V. Which is an equivalent equat

Kamila [148]

Since:
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2 years ago

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