T= total
<span>Money spent is: </span>
48+ 1/3 (T-48) = 1/2 T
One equation for one unknown, solve:
48 + 1/3 T -1/3*48= 1/2 T
48 - 16 =1/2 T- 1/3 T
32= 1/6 T
T= 6*32
<span>T=192
</span>192-48=144 money left after watch
1/3*144=48 third of leftover, spent on pen
<span>144-48=96 left which is half of 192. </span>
<u><em>Answer:</em></u>
Jenna did 16 regular haircuts
Jenna did 8 haircuts with coloring
<u><em>Explanation:</em></u>
Assume that the number of regular haircuts is x and the number of haircuts plus coloring is y
<u>We are given that:</u>
<u>1- Jenna did a total of 24 clients, this means that:</u>
x + y = 24
This can be rewritten as:
x = 24 - y ...............> equation I
<u>2- regular haircuts cost $25, haircuts plus coloring cost $42 and she earned a total of $736. This means that:</u>
25x + 42y = 736 ..........> equation II
<u>Substitute with equation I in equation II and solve for y as follows:</u>
25x + 42y = 736
25(24-y) + 42y = 736
600 - 25y + 42y = 736
17y = 136
y = 8
<u>Substitute with y in equation I to get x as follows:</u>
x = 24 - y
x = 24 - 8
x = 16
<u>Based on the above:</u>
Jenna did 16 regular haircuts
Jenna did 8 haircuts with coloring
Hope this helps :)
X = E/W dimension
<span>y = N/S dimension </span>
<span>4x + 4x + 2y + 2y = 64 </span>
<span>8x + 4y = 64 </span>
<span>4y = 64 - 8x </span>
<span>y = 16 - 2x </span>
<span>Area = xy = x(16 - 2x) = 16x - 2x^2 </span>
<span>Maximum of y = ax^2 + bx + c is when x = -b / 2a </span>
<span>so x = -16 / -4 = 4 </span>
Malcolm's remaining distance is approximately
1370 - 470 - 430 = 470
This corresponds to selection ...
D) 470 miles
Hello! The answer to your question would be as followed:
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
-79-(7*w+3*(4*w-1)=0
-79 - (7w + 3 • (4w - 1)) = 0
Pulling out like terms :
Pull out like factors :
-19w - 76 = -19 • (w + 4)
-19 • (w + 4) = 0
Equations which are never true :
Solve : -19 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Solving a Single Variable Equation :
Solve : w+4 = 0
Subtract 4 from both sides of the equation :
w = -4
w = -4
