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Karolina [17]
1 year ago
11

When Θ = 5 pi over 6, what are the reference angle and the sign values for sine, cosine, and tangent?

Mathematics
2 answers:
stira [4]1 year ago
3 0
Note that (5π)/6 radians = 150°. Therefore the given angle is in quadrant 2.

Refer to the figure shown below.

Reference angles are measured relative to the horizontal axis.
Therefore the reference angle in each quadrant is π/6 radians or 30°.
Denote the reference angle as θ'.
Then, in quadrant 1,
cos θ' = √3/2,  sin θ' = 1/2,  tan θ' = √3.

Because we are in quadrant 2,
  sin θ' = π/6;
  sin(5π/6) is positive, but cos (5π/6) and tan (5π/6) are negative.

 Answer:
5π/6 is in quadrant 2.
The reference angle, θ' = π/6.
sin(5π/6) is positive, cosine and tangent are negative.

jarptica [38.1K]1 year ago
3 0

Answer:

5π/6 is in quadrant 2.

The reference angle, θ' = π/6.

sin(5π/6) is positive, cosine & tangent are both negative

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<u>Answer:</u>

The maximum number of turkey sandwiches Ben could have sold is 6.

<u>Step-by-step explanation:</u>

We are given that turkey sandwiches cost $2.50 and veggie wraps cost $3.50 at a snack stand.

Given the information, we are to find the maximum value of turkey sandwiches Ben could have sold.

2 . 5 0 x + 3 . 5 0 y \leq 3 0

Number of veggie wraps sold (y) = 4

2.50x + 3.50(4) <   30

2.50x + 14          <   30

<u>           - 14               -14 </u>

2.50x                   <   16

x

x

The maximum number of turkey sandwiches Ben could have sold is 6.

4 0
2 years ago
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Tyrell Otis deposited his IRS refund check for $760 at 5% and made no other deposits or withdrawals. How much simple interest di
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Answer:

He earned $114 in interest.

The final amount in the account is $874

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Initial balance (b): $760

Interest rate (i): 0.05

Period (n): 3 months

Simple interest applications yield the same amount in interest every period. Therefore, the total simple interest earned can be defined by:

I = n*B*i\\I= 3*760*0.05\\I=114

The final amount (A) in the account is the initial balance plus the interest earned in 3 months.

A = 760 +114\\A=874

He earned $114 in interest and the final amount in the account is $874

6 0
1 year ago
A shower has a flow rate of 2.3 gallons per minute. If a person takes an average of 6 showers per week and the average length of
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Answer:

161,460 gallons are used in a year.

Step-by-step explanation:

1 shower- 2.3×15=34.5

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There is 52 weeks in a year.

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8 0
2 years ago
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The interest rate she would pay would be is $7,200
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2 years ago
Which of the following is the expansion of (3c + d2)6?
vovangra [49]

Answer: Option A) 729c^6 + 1,458c^5d^2 + 1,215c^4d^4 + 540c^3d^6 + 135c^2d^8 + 18cd^{10} + d^{12} is the correct expansion.

Explanation:

on applying binomial theorem,  (a+b)^n=\sum_{r=0}^{n} \frac{n!}{r!(n-r)!} a^{n-r} b^r

Here a=3c, b=d^2 and n=6,

Thus, (3c+d^2)^6=\sum_{r=0}^{6} \frac{6!}{r!(6-r)!} (3c)^{n-r} (d^2)^r

⇒ (3c+d^2)^6= \frac{6!}{(6-0)!0!} (3c)^{6-0}.(d^2)^0+\frac{6!}{(6-1)!1!} (3c)^{6-1}.(d^2)^1+\frac{6!}{(6-2)!2!} (3c)^{6-2}.(d^2)^2+\frac{6!}{(6-3)!3!} (3c)^{6-3}.(d^2)^3+\frac{6!}{(6-4)!4!} (3c)^{6-4}.(d^2)^4+\frac{6!}{(6-5)!5!} (3c)^{6-5}.(d^2)^5+\frac{6!}{(6-6)!6!} (3c)^{6-6}.(d^2)^6

⇒(3c+d^2)^6= \frac{6!}{(6-)!0!} (3c)^6.d^0+\frac{6!}{(5)!1!} (3c)^5.d^2+\frac{6!}{(4)!2!} (3c)^4.d^4+\frac{6!}{(6-3)!3!} (3c)^3.d^6+\frac{6!}{(2)!4!} (3c)^2.d^8+\frac{6!}{(1)!5!} (3c).d^{10}+\frac{6!}{(0)!6!} (3c)^0.d^{12}

⇒(3c+d^2)^6=(3c)^6.d^0+\frac{720}{120} (3c)^5.d^2+\frac{720}{48} (3c)^4.d^4+\frac{720}{36} (3c)^3.d^6+\frac{720}{48} (3c)^2.d^8+\frac{720}{120} (3c).d^{10}+.d^{12}

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3 0
2 years ago
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