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Lera25 [3.4K]
2 years ago
5

Tyrell Otis deposited his IRS refund check for $760 at 5% and made no other deposits or withdrawals. How much simple interest di

d his money earn in 3 months? What is the final amount in the account?​
Mathematics
1 answer:
Helga [31]2 years ago
6 0

Answer:

He earned $114 in interest.

The final amount in the account is $874

Step-by-step explanation:

Initial balance (b): $760

Interest rate (i): 0.05

Period (n): 3 months

Simple interest applications yield the same amount in interest every period. Therefore, the total simple interest earned can be defined by:

I = n*B*i\\I= 3*760*0.05\\I=114

The final amount (A) in the account is the initial balance plus the interest earned in 3 months.

A = 760 +114\\A=874

He earned $114 in interest and the final amount in the account is $874

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Find three different surfaces that contain the curve r(t) = t^2 i + lnt j + (1/t)k
Viefleur [7K]

solution:

Consider the curve: r(t) = t²i +(int)j + 1/t k

X= t² , y = int ,z = 1/t

Using, x = t², z = 1/t

                    X = (1/z)²

Xz²= 1

Using y = int, z= 1/t

Y = in│1/z│

Using x = t², y = int

Y = int

= in(√x)

Hence , the required surface are,

Xz² = 1

Y = in│1/z│

Y= in(√x)


7 0
2 years ago
Charles has a collection of dimes and quarters worth $1.25. He has 8 coins. Write a systems of equations to represent this situa
Dima020 [189]

Answer:

* The systems of equations are:

# d + q = 8 ⇒ (1)

# 10d + 25q = 125 ⇒ (2)

Charles has 5 dimes and 3 quarters

Step-by-step explanation:

* Lets explain how to solve the problem

- Charles has a collection of dimes and quarters worth $1.25

- He has 8 coins

* To solve the problem remember that:

# 1 dim = 10 cents

# 1 quarter = 25 cents

# 1 dollar = 100 cents

- Assume that the number of dimes is d and the number of

 quarter is q

∵ Charles has 8 coins

- The number of dimes and the number of quarters equal the

  number of the coins

∴ d + q = 8 ⇒ (1)

∵ 1 dime = 10 cents

∴ The value of dimes = 10 × d = 10d

∵ 1 quarter = 25 cents

∴ The value of quarters = 25 × q = 25q

∵ The collection worth $1.25

∵ 1 dollar = 100 cents

∴ The collection worth = 1.25 × 100 = 125 cents

∴ 10d + 25q = 125 ⇒ (2)

* The systems of equations are:

# d + q = 8 ⇒ (1)

# 10d + 25q = 125 ⇒ (2)

* Lets solve the equations

- Multiply equation (1) by (-10) to eliminate d

∴ -10d + -10q = -80 ⇒ (3)

- Add equations (2) and (3)

∴ 15q = 45

- Divide both sides by 15

∴ q = 3

- Substitute the value of q in equation (1) to find the value of d

∴ d + 3 = 8

- Subtract 3 from both sides

∴ d = 5

∵ d represents the number of dimes and q represents the number

  of quarters

∴ Charles has 5 dimes and 3 quarters

4 0
2 years ago
PLEASE HELP! Given the following equation of an exponential function N= 40.25(1.0394)^t determine the base, b, of the exponentia
NeTakaya
The exponential equation in its generic form is:
 y = A * (b) ^ t
 Where,
 A: initial amount
 b: base (Growth rate for b> 1. Decrease rate for b <1.)
 t: time.
 We have then that the equation is:
 N = 40.25 (1.0394) ^ t
 The base is:
 b = 1.0394> 1 (it is a growth rate)
 Answer:
 
The base, b, of the exponential model is:
 
b = 1.0394
 the base is a growth rate
5 0
2 years ago
Consider △RST and △RYX. If the triangles are similar, which must be true? A. RY/YS=RX/XT=XY/TS B.RY/RS=RX/RT=XY/TS C.RY/RS=RX/RT
trasher [3.6K]

Answer:

B.RY/RS=RX/RT=XY/TS

Step-by-step explanation:

If Triangles RST and RYX are similar, then the ratio of their corresponding sides is:

\dfrac{RS}{RY}= \dfrac{ST}{YX}=\dfrac{RT}{RX}\\$This could also be written by switching the numerator and denominators as:\\\dfrac{RY}{RS}= \dfrac{XY}{TS}=\dfrac{RX}{RT}

Out of the given options, Option B is true.

3 0
2 years ago
The sides of a square field are 32 meters. A sprinkler in the center of the field sprays a circular area with a diameter that co
olga2289 [7]
You find the area not touched by the sprinkler by subtracting the area of the circle from the area of the square.  The area of the square is 32*32 which is 1024.  The area of the circle is found by multiplying 3.14 by the radius squared.  Our radius is half the diameter of 32, so r = 16.  A=3.14(16)(16) which gives us an area of the circle to be 803.84.  Subtracting the 2 areas, square minus circle, is 1024-803.84=220.16 meters squared.
5 0
2 years ago
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