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FinnZ [79.3K]
2 years ago
5

In the game of blackjack played with one​ deck, a player is initially dealt 2 different cards from the 52 different cards in the

deck. a winning​ "blackjack" hand is won by getting 1 of the 4 aces and 1 of 16 other cards worth 10 points. the two cards can be in any order. find the probability of being dealt a blackjack hand. what approximate percentage of hands are winning blackjack​ hands?
Mathematics
1 answer:
Tpy6a [65]2 years ago
6 0

We are given here that a blackjack hand consists of:

1 of the 4 aces = 4 / 52

1 of the 16 cards worth 10 points (10, jack, queen, king) = 16 / 52

 

So assuming that cards are dealt without replacement, therefore the probability of getting a blackjack hand is:

<span>P = 1st is ace * 2nd is 10 pt card + 1st is 10 pt card * 2nd is ace</span>

P = (4 / 52) * (16 / 51) + (16 / 52) * (4 / 51)

P = 0.04827 = 4.83%

 

Therefore there is a 4.83% probability to get a blackjack hand.

<span> </span>

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A newly drilled water well produces 50,000 quarts of water per week. With no new water feeding the well, the production drops by
Sveta_85 [38]

Answer:

Total amount of water = 5,200,000

Step-by-step explanation:

Given:

water produced = 50,000 quarts of water per week

Production drop = 5% = 0.05 per year

Number of week in year = 52 week

Find:

Total amount of water

Computation:

Sum = a / r

a = 50,000 x 52

a = 2,600,000

Sum = a / [1-r]

Sum = 2,600,000 / 5%

Sum = 2,600,000 / 0.05

Total amount of water = 5,200,000

5 0
1 year ago
Side AB of square ABCD is parallel to the Y axis and the perimeter of ABCD is 36. If the coordinates of point B is (5,17) . What
Zarrin [17]
<h3>Answer: (C) (14,8)</h3>

============================================

Explanation:

The perimeter of the square is 36, so each side length is 36/4 = 9 units.

Point B is located at (5,17). We move down 9 units to get to (5,8), which is the location of point A. Then we move 9 units to the right to arrive at (14,8) which is point D's location.

Or we could go from B = (5,17) to C = (14,17) and then to D = (14,8). Each time we move 9 units.

8 0
1 year ago
The formula for the future value V (in dollars) of an investment earning simple interest is V=p+prt, where p (in dollars) is the
zhannawk [14.2K]

a)

V=p+prt

now we solve for P

V=P (1+rt)

Divide both sides by (1+rt)

P=V÷(1+rt)...answer

b)

P=V÷(1+rt)

P=3,000÷(1+0.06×5)

P=2,307.69

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2 years ago
In American football, the playing field is 53.33 yards (yd) wide by 120 yards (yd) long. For a special game, the field staff wan
nataly862011 [7]

Answer:

214

Step-by-step explanation:

The playing field is 53.33 yards wide and 120 yards long you would need to find the area so multiply 53.33 by 120 yards. That equals 6399.6 , the thickness they are applying is 1.2 millimeters. You would divide the area, 6399.6 by 1.2 which would equal 5333. Divide that by 25 gallons and it equals 213.32, you would need to purchase 214, rounded.

3 0
2 years ago
Read 2 more answers
Assume that the number of hours of daylight in New Orleans in 1994 is given by the function D(x) = 7 3 sin 2π 365 x + 35 3 , whe
Bas_tet [7]

Answer:

Here, the given function that represents the number of hours of daylight in New Orleans in 1994 is,

D(x) = \frac{7}{3} \sin \frac{2\pi }{365}x + \frac{35}{3}

Where,

x = the number of days after March 21

The number of days from 1 January to march 21 = 80

If x = -80, then,

D(-80) = \frac{7}{3} \sin \frac{2\pi }{365}(-80) + \frac{35}{3}

            =\frac{7}{3} \sin (-\frac{160 \pi}{365}) + \frac{35}{3}

            =-\frac{7}{3} \sin (\frac{160 \pi}{365}) + \frac{35}{3}

            =-\frac{7}{3}(0.98130)+\frac{35}{3}

           \approx 9.38

Therefore, the number of hours of daylight on January 1 are 9.38.

The number of days from march 21 to may 4 = 44

If x =44, then,

D(44) = \frac{7}{3} \sin \frac{2 \pi}{365}(44) + \frac{35}{3}

         =\frac{7}{3} \sin (\frac{88 \pi}{365}) + \frac{35}{3}

         =\frac{7}{3}(0.6870) + \frac{35}{3}

         \approx 13.27

Therefore, the number of hours of daylight on May 4 are 13.27.

The number of days from October 28 to may 4 = 221

If x = 221, then,

D(221) = \frac{7}{3} \sin \frac{2 \pi}{365}(221) + \frac{35}{3}

           =\frac{7}{3} \sin (\frac{442 \pi}{365}) + \frac{35}{3}

           =\frac{7}{3}(-0.6152)+\frac{35}{3}

           \approx 10.23

Therefore, the number of hours of daylight on October 28 are 10.23.

4 0
2 years ago
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