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FinnZ [79.3K]
2 years ago
5

In the game of blackjack played with one​ deck, a player is initially dealt 2 different cards from the 52 different cards in the

deck. a winning​ "blackjack" hand is won by getting 1 of the 4 aces and 1 of 16 other cards worth 10 points. the two cards can be in any order. find the probability of being dealt a blackjack hand. what approximate percentage of hands are winning blackjack​ hands?
Mathematics
1 answer:
Tpy6a [65]2 years ago
6 0

We are given here that a blackjack hand consists of:

1 of the 4 aces = 4 / 52

1 of the 16 cards worth 10 points (10, jack, queen, king) = 16 / 52

 

So assuming that cards are dealt without replacement, therefore the probability of getting a blackjack hand is:

<span>P = 1st is ace * 2nd is 10 pt card + 1st is 10 pt card * 2nd is ace</span>

P = (4 / 52) * (16 / 51) + (16 / 52) * (4 / 51)

P = 0.04827 = 4.83%

 

Therefore there is a 4.83% probability to get a blackjack hand.

<span> </span>

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Step-by-step explanation:

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1 year ago
1. Mac is about to sue his contractor who promised to install a water tank that holds 1880 gallons of water. Mac knows that 1880
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Answer:

option C.

Yes, the water tank is about 245 cubic feet too small

Step-by-step explanation:

step 1

Determine the volume of the cylindrical tank

we know that

The volume of a cylinder is equal to

V=\pi r^{2} h

Remember that

1\ ft=12\ in

we have

r=6\ ft\\h=2\ ft\ 2\ in=2+(2/12)=\frac{13}{6}\ ft

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V=(3.14)(6)^{2}(\frac{13}{6})

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Compare with 251 cubic feet

244.92\ ft^3 < 251\ ft^3

therefore

Yes, the water tank is about 245 cubic feet too small

8 0
2 years ago
The XO Group Inc. conducted a survey of 13,000 brides and grooms married in the United States and found that the average cost of
slavikrds [6]

Answer:

a) 0.0392

b) 0.4688

c) At least $39,070 to be among the 5% most expensive.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 29858, \sigma = 5600

a. What is the probability that a wedding costs less than $20,000 (to 4 decimals)?

This is the pvalue of Z when X = 20000. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{20000 - 29858}{5600}

Z = -1.76

Z = -1.76 has a pvalue of 0.0392.

So this probability is 0.0392.

b. What is the probability that a wedding costs between $20,000 and $30,000 (to 4 decimals)?

This is the pvalue of Z when X = 30000 subtracted by the pvalue of Z when X = 20000.

X = 30000

Z = \frac{X - \mu}{\sigma}

Z = \frac{30000 - 29858}{5600}

Z = 0.02

Z = 0.02 has a pvalue of 0.5080.

X = 20000

Z = \frac{X - \mu}{\sigma}

Z = \frac{20000 - 29858}{5600}

Z = -1.76

Z = -1.76 has a pvalue of 0.0392.

So this probability is 0.5080 - 0.0392 = 0.4688

c. For a wedding to be among the 5% most expensive, how much would it have to cost (to the nearest whole number)?

This is the value of X when Z has a pvalue of 0.95. So this is X when Z = 1.645.

Z = \frac{X - \mu}{\sigma}

1.645 = \frac{X - 29858}{5600}

X - 29858 = 5600*1.645

X = 39070

The wedding would have to cost at least $39,070 to be among the 5% most expensive.

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Answer:

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