Answer:
StartFraction 1 Over 15 EndFraction left-parenthesis 10 h plus 60 right-parenthesis equals StartFraction 1 Over 10 Endfraction left-parenthesis 10 h right-parenthesis
Step-by-step explanation:
The desired equation equates 1/15 of the amount Lindsay earned with 1/10 the amount without the bonus:
StartFraction 1 Over 15 EndFraction left-parenthesis 10 h plus 60 right-parenthesis equals StartFraction 1 Over 10 Endfraction left-parenthesis 10 h right-parenthesis
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<em>Comment on the form of the answer</em>
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1.55 / 1 = x / 3.5....$ 1.55 to 1 lb = $ x to 3.5 lbs
first one <==
it could have also been : 1 / 1.55 = 3.5 / x...but that is not an answer choice
<em><u>The intervals included in solution are:</u></em>

<em><u>Solution:</u></em>
Given that,
A boat tour guide expects his tour to travel at a rate of x mph on the first leg of the trip
On the return route, the boat travels against the current, decreasing the boat's rate by 10 mph
The group needs to travel an average of at least 24 mph
<em><u>Given inequality is:</u></em>

<em><u>We have to solve the inequality</u></em>




When we multiply or divide both sides by negative number, then we must flip the inequality sign


This is attached as figure below
From the attached table,

<em><u>Therefore, solution set is given as</u></em>:

The first one is; BC
The second one is; Reflection
The third one is; A
The fourth one is; Length
Answer:
The area of the shaded region is 42.50 cm².
Step-by-step explanation:
Consider the figure below.
The radius of the circle is, <em>r</em> = 5 cm.
The sides of the rectangle are:
<em>l</em> = 11 cm
<em>b</em> = 11 cm.
Compute the area of the shaded region as follows:
Area of the shaded region = Area of rectangle - Area of circle
![=[l\times b]-[\pi r^{2}]\\\\=[11\times 11]-[3.14\times 5\times 5]\\\\=121-78.50\\\\=42.50](https://tex.z-dn.net/?f=%3D%5Bl%5Ctimes%20b%5D-%5B%5Cpi%20r%5E%7B2%7D%5D%5C%5C%5C%5C%3D%5B11%5Ctimes%2011%5D-%5B3.14%5Ctimes%205%5Ctimes%205%5D%5C%5C%5C%5C%3D121-78.50%5C%5C%5C%5C%3D42.50)
Thus, the area of the shaded region is 42.50 cm².