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Brums [2.3K]
2 years ago
12

Determine whether or not the two equations below have the same solution. In two or more complete sentences, explain your rationa

le
2/3x + 3/4 = 8
8x=87
Mathematics
2 answers:
Dimas [21]2 years ago
5 0
These equations do match up. All you have to do is find the solution to the first equation. After that, plug in that solution to the second equation. If it makes the equation true, then the equations match. 

Hope this helps!
zzz [600]2 years ago
5 0
If the two equation have the same solution, the x value of each will be equal.  So we solve each equation for x and see if they are equal...

2x/3+3/4=8

(8x+9)/12=8

8x+9=96

8x=87

x=87/8

And the other equation was:

8x=87 so

x=87/8

Since x=x the equations do have a solution 
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Unless otherwise specified, the domain of a function f is assumed to be the set of all real numbers x for which f(x) is a real n
e-lub [12.9K]

Answer:

See Below

Step-by-step explanation:

The function is a piecewise function defined as:

N(t)=\left \{ {{25t+150} \ 0 \leq t \leq 6 \atop {\frac{200+80t}{2+0.05t} \ t \geq 8}} \right.

a)

We need to find the limit of the function as t goes to infinity. This means what is the max value of fish in the pond given times goes to infinity (on an on).

We will take the 2nd part of the equation since t falls into that range, t is infinity, which is definitely greater than 8.

\lim_{t \to \infty} \frac{200+80t}{2+0.05t} \\\lim_{n \to \infty} \frac{80t}{0.05t}\\ \lim_{n \to \infty} \frac{80}{0.05} =1600

This means the maximum number of fish at this pond is 1600, no matter how long it goes on.

b)

A function is continuous at a point if we have the limit and the functional value at that point same.

Functional value at t = 8 is (we use 2nd part of equation):

\frac{200+80t}{2+0.05t}\\\frac{200+80(8)}{2+0.05(8)}\\=350

We do have a value and limit also goes to this as t approaches 8.

So, function is continuous at t = 8

c)

We want to find is there a "time" when the number of fishes in the pond is 250, during t from 0 to 6. We plug in 250 into N(t) and try to find t. Make sure to use the 1st part of the piece-wise function. Shown below:

N(t)=25t+150\\250=25t+150\\25t=250-150\\25t=100\\t=4

The time is 4 years when the number of fishes in the pond is 250

6 0
2 years ago
Dr. Mitchell, an animal veterinarian, collected data during animal examinations on the kind of animal a boy or girl has as a pet
CaHeK987 [17]

Can you plz show us the data collected.

8 0
2 years ago
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Points B and C lie on a circle with center O and radius r = 5 units. If the length of BCwn is 10.91 units, what is m∠BOC in radi
saul85 [17]
2.182 radians
Good look!
3 0
2 years ago
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At a Psychology final exam, the scores are normally distributed with a mean 73 points and a standard deviation of 10.6 points. T
USPshnik [31]

Answer:

The score that separates the lower 5% of the class from the rest of the class is 55.6.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

\mu = 73, \sigma = 10.6

Find the score that separates the lower 5% of the class from the rest of the class.

This score is the 5th percentile, which is X when Z has a pvalue of 0.05. So it is X when Z = -1.645.

Z = \frac{X - \mu}{\sigma}

-1.645 = \frac{X - 73}{10.6}

X - 73 = -1.645*10.6

X = 55.6

The score that separates the lower 5% of the class from the rest of the class is 55.6.

3 0
2 years ago
Given: mTRV = 60° mTRS = (4x)° Prove: x = 30 What is the missing reason in step 3? substitution property of equality angle addit
mihalych1998 [28]

Answer: Angle addition postulate.

Explanation: If \angle TRV= 60^{\circ} and \angle TRS=4x^{\circ}

here, if we have to prove x=30

If there is a condition that TR is a line which meets with the line segment VS at point R then by the Angle addition postulate,  we can say that \angle TRV+\angle TRS=180^{\circ}⇒x=30^{\circ}

But,

In option (1) substitution property of equality

If there is condition that  \angle TRV=\angle TRS

then we can use  substitution property of equality,

And, in this case 4x^{\circ}=60^{\circ}⇒x=15^{\circ}

which is wrong. So, we can not use this property here.

In option (3) subtraction property of equality

There is no use of this property to find the value x.

In option (4) addition property of equality

There is no use of this property to find the value x.

8 0
2 years ago
Read 2 more answers
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