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mel-nik [20]
2 years ago
14

a group of 12 adults and 26 children go to a theme park . The total costs of the tickets was £1804.80. An adults ticket costs 51

.60 find the cost of a ticket for a child
Mathematics
2 answers:
nadya68 [22]2 years ago
6 0

Answer:

The cost of a ticket for a child is £45.6

Step-by-step explanation:

- A group of 12 adults and 26 children go to a theme park

- The total costs of the tickets was £1804.8

- An adults ticket costs £51.6

- We need to find the cost of a ticket for a child

- Assume that the price of a ticket for a child is £x

∵ The group has 26 children

∴ The cost of children tickets = 26 × (x)

∵ The group has 12 adults

∵ The cost of the adult ticket = £51.6

∴ The cost of adult tickets = 12 × 51.6

∵ The total cost of tickets = 26 × (x) + 12 × 51.6

∴ The total cost of tickets = 26 x + 619.2

∵ The total costs of the tickets was £1804.8

- Equate the two expressions of the total cost

∴ 26 x + 619.2 = 1804.8

- Subtract 619.2 from both sides

∴ 26 x = 1185.6

- Divide both sides by 26

∴ x = 45.6

* The cost of a ticket for a child is £45.6

OlgaM077 [116]2 years ago
4 0

Answer:

12 Adults is 51.60 x 12=619.20

In order to find the children ticket you need to take the total cost minus the adults ticket.

1804.80 - 619.20 = 1185.60(26 children ticket)

to find a children ticket you take (total 26 children ticket) subtract 26

1185.60 divide 26 = 45.60

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she walked 6 miles.

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We can solve this using a rule of three:

If she walks 4 miles in 1 hour, how many hours did she walk in 1.5 hours?

1 hour           4 miles

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2 years ago
Emilia saved nickels, dimes, and quarters in a jar. She had as many quarters as dimes, but twice as many nickels as dimes. If th
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Let us assume number of nickels = n,

number of dimes = d and

number of quarters = q.

Total number of coins = 844.

We can setup a statement "number of nickels + number of dimes +number of quarters = Total coins.

And we can setup an equation for the above statement as

n+d+q = 844            ---------------------equation(1).

We also given: Emilia had as many quarters as dimes.

Therefore, number of quarters = number of dimes.

So, we can setup another equation as

q = d                          ------------------------equation(2).

Also given : "twice as many nickels as dimes".

We can setup another equation for this statement as

n = twice of number of dimes

or n= 2d                -------------------------- equation (3).

We got three equations.

Let us solve system of three equation by substitution method.

Substituting q = d and  n= 2d  in equation (1), we got

n+d+q = 844      => 2d +d + d = 844.

Adding d's, we get

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Dividing both sides by 4, we get

\frac{4d}{4}=\frac{844}{4}

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Therefore number of dimes = 211.

Let us find number of nickels and number of quarter coins now.

We know, number of quarters = number of dimes.

Therefore, number of qurters = 221.

Total number of coins = 844.

Therefore, number of nickels = 844 -  (number of quarters + number of dimes).

= 844 -(221+221) = 844 - 442

= 402.

So, the number of nickels =402.

Let us find the total values of all the coins.

A nickel = $0.05

A dime = $0.10

A quarter = $0.25.

Total value = 0.05 *(number of nickels) + 0.10*(number of dimes) + 0.25*(number of quarters).

= 0.05* 402 + 0.10 *221 + 0.25*221.

= 20.10 + 22.10 + 55.25.

= 97.45.

Therefore, total value of all 844 coins = $97.45.

Emilia had saved $97.45.


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