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Kamila [148]
2 years ago
11

Ruth left her home at 9 am and walked to the library. She got to the library at 10 30 am. Ruth walked at a speed of 4 mph. (a) W

ork out the distance Ruth walked.
Mathematics
1 answer:
sveticcg [70]2 years ago
8 0

Answer:

she walked 6 miles.

Step-by-step explanation:

We know that Ruth walks at a speed of 4 mph and it took her 1.5 hours to walk from her home to the library (from 9 to 10.30).

We can solve this using a rule of three:

If she walks 4 miles in 1 hour, how many hours did she walk in 1.5 hours?

1 hour           4 miles

1.5 hours       x miles

Solving for x we get:

x=\frac{1.5(4)}{1} =6 miles

Thus, she walked a distance of 6 miles

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Answer:

r = 0.9825; good correlation.

Step-by-step explanation:

One formula for the correlation coefficient is  

r = \dfrac{n\sum{xy} - \sum{x} \sum{y}}{\sqrt{n\left [\sum{x}^{2}-\left (\sum{x}\right )^{2}\right]\left [\sum{y}^{2}-\left (\sum{y}\right )^{2}\right]}}

The calculation is not difficult, but it is tedious.

1. Calculate the intermediate numbers

We can display them in a table.

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      -3   -40    120     9     1600

       1      12      12      1        144

       5    72   360   25      5184

     <u>  7</u>   <u>137</u>  <u> 959</u>   <u>49</u>    <u>18769 </u>

Σ = 10   181  1451   84   25697

2. Calculate the correlation coefficient

r = \dfrac{n\sum{xy} - \sum{x} \sum{y}}{\sqrt{\left [n\sum{x}^{2}-\left (\sum{x}\right )^{2}\right]\left [n\sum{y}^{2}-\left (\sum{y}\right )^{2}\right]}}\\\\= \dfrac{4\times 1451 - 10\times 181}{\sqrt{[4\times 84 - 10^{2}][4\times25697 - 181^{2}]}}\\\\= \dfrac{5804 - 1810}{\sqrt{[336 - 100][102788 - 32761]}}\\\\= \dfrac{3994}{\sqrt{236\times70027}}\\\\= \dfrac{3994}{\sqrt{16526372}}\\\\= \dfrac{3994}{4065}\\\\= \mathbf{0.9825}

The closer the value of r is to +1 or -1, the better the correlation is. The values of x and y are highly correlated.

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