Answer:
The probability that a particular driver had exactly two speeding violations is 0.009.
Step-by-step explanation:
We are given that a sample of 2,000 licensed drivers revealed the following number of speeding violations;
<u>Number of Violations</u> <u>Number of Drivers</u>
0 1,910
1 46
2 18
3 12
4 9
5 or more <u> 5 </u>
<u>Total</u> <u> 2000 </u>
<u />
Now, the data means that 1,910 drivers had 0 speeding violations and so on.
Now, we have to find the probability that a particular driver had exactly two speeding violations, that means;
Number of drivers having exactly two speeding violations = 18
Total numbers of drivers = 2000
So, the required probability =
=
= <u>0.009</u>
Answer:
992
Step-by-step explanation:
Divide 1000 by 26.
The answer is 38 and some left over. We don't care what the leftover is because it is nearly 0.5 and that means 13 people were left over.
Take the integer value (38) and multiply it by 26. You get 988.
You want there to be 4 left over. 4 + 988 = 992. That's one way of doing the problem.
Answer:
a) 90.695 lb
b) 85.305 lb
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

(a) The 65th percentile
X when Z has a pvalue of 0.65. So X when Z = 0.385.




(b) The 35th percentile
X when Z has a pvalue of 0.35. So X when Z = -0.385.



