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svet-max [94.6K]
2 years ago
5

A sample of 2,000 licensed drivers revealed the following number of speeding violations. Number of Violations Number of Drivers

0 1,910 1 46 2 18 3 12 4 9 5 or more 5 Total 2,000 Click here for the Excel Data File What is the probability that a particular driver had exactly two speeding violations
Mathematics
1 answer:
Arturiano [62]2 years ago
6 0

Answer:

The probability that a particular driver had exactly two speeding violations is 0.009.

Step-by-step explanation:

We are given that a sample of 2,000 licensed drivers revealed the following number of speeding violations;

           <u>Number of Violations</u>               <u>Number of Drivers</u>

                         0                                              1,910

                          1                                                46

                         2                                                 18

                         3                                                 12

                         4                                                  9

                         5 or more                             <u>       5      </u>

                        <u>Total</u>                                      <u>    2000  </u>

<u />

Now, the data means that 1,910 drivers had 0 speeding violations and so on.

Now, we have to find the probability that a particular driver had exactly two speeding violations, that means;

Number of drivers having exactly two speeding violations = 18

 Total numbers of drivers = 2000

So, the required probability  =  \frac{\text{No. of drivers having two speeding violations}}{\text{Total no. of drivers}}

                                               =  \frac{18}{2000}  =  <u>0.009</u>

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Answer:

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Step-by-step explanation:

Given as :

The total of digits having ones and hundreds = 900

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And The number of hundreds digit = H

So, According to question

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Or , 99 H = 882

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Hence The number of once is 9.1  and The number of hundreds is 8.9

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What is the equation of a line that is parallel to the line 2x + 5y = 10 and passes through the point (–5, 1)? Check all that ap
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So the right options are:

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Further explanation:

Given equation of line is:

2x+5y=10

We have to convert it into point-slope form

2x+5y=10\\5y=-2x+10\\Dividing\ both\ sides\ by\ 5\\y=-\frac{2}{5}x+\frac{10}{5}\\y=-\frac{2}{5}x+2

The co-efficient of x is the slope of the line

So,

m= -\frac{2}{5}

As the required line is parallel to given line, it will also have same slope.

Let m1 be the slope of required line

Then the line will be:

y=m_1x+b

Putting the value of slope

y=\frac{2}{5}x+b

Putting (-5,1) in the equation to find the value of b

1=-\frac{2}{5}(-5)+b\\1=2+b\\b=1-2\\b=-1

Putting the values of slope and b in equation

y=-\frac{2}{5}x-1

Multiplying the whole equation by 5 will give us:

5y = -2x-5

2x+5y = -5

Another form of equation of line is Point-slope form

y-y_1=m(x-x_1)

Putting the values of slope and point in the equation, we get

y-1=-\frac{2}{5}(x+5)

So the right options are:

y=-\frac{2}{5}x-1

2x+5y = -5

y-1=-\frac{2}{5}(x+5)

Keywords: Point-Slope form, Parallel lines

Learn more about point slope form at:

  • brainly.com/question/4464845
  • brainly.com/question/4522984

#LearnwithBrainly

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