Answer:
Company A is a better deal than Company B for the number of miles greater than 295 miles
Step-by-step explanation:
Let
y ----> the charge per week in dollars
x ----> the number of miles
we have
<em>Company A</em>
-----> equation A
<em>Company B</em>
-----> equation B
Solve the system by substitution
Equate equation A and equation B and solve for x
For x=295 miles the charge in Company A and Company B is the same
therefore
Company A is a better deal than Company B for the number of miles greater than 295 miles
To solve this, we must first find out the cost-per-ounce of a cup of coffee. Assuming that the rates are flat, then we can just divide the 8-dollar-cost by the 4-ounce cup that it buys.
8 / 4 = 2
The cost-per-ounce of a cup of coffee is $2.
Now, we just have to multiply the cost-per-ounce by the amount of coffee we want to find out the cost of.
2 * 3 = 6
With all else constant, a 3-ounce cup of coffee would cost $6.
Hope that helped! =)
The length of the new tank is 5 times bigger than the old one, so 154×5=770. As a result, the capacity of the new tank is 770L. Hope it help!
Answer:
0.514
Step-by-step Explantion:
Denominator = 500 = 2^2 * 5^3
257/500 = 257/2^2*5^3 = 2*257/2*2^2*5^3 = 514/2^3*5^3 = 514/(2*5)^3 = 514/10^3 = 0.514
Answer:
![4x^5\sqrt[3]{3x}](https://tex.z-dn.net/?f=%204x%5E5%5Csqrt%5B3%5D%7B3x%7D%20)
Step-by-step explanation:
I'm not sure I understand the problem, but I think it's this:
![\sqrt[3]{16x^7} \times \sqrt[3]{12x^9} =](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B16x%5E7%7D%20%5Ctimes%20%5Csqrt%5B3%5D%7B12x%5E9%7D%20%3D%20)
![= \sqrt[3]{16 \times 12 \times x^{16}}](https://tex.z-dn.net/?f=%3D%20%5Csqrt%5B3%5D%7B16%20%5Ctimes%2012%20%5Ctimes%20x%5E%7B16%7D%7D)
![= \sqrt[3]{192 \times x^{15} \times x}](https://tex.z-dn.net/?f=%3D%20%5Csqrt%5B3%5D%7B192%20%5Ctimes%20x%5E%7B15%7D%20%5Ctimes%20x%7D)
![= \sqrt[3]{64 \times 3 \times (x^5)^3 \times x}](https://tex.z-dn.net/?f=%20%3D%20%5Csqrt%5B3%5D%7B64%20%5Ctimes%203%20%5Ctimes%20%28x%5E5%29%5E3%20%5Ctimes%20x%7D%20)
![= \sqrt[3]{4^3 \times 3 \times (x^5)^3 \times x}](https://tex.z-dn.net/?f=%20%3D%20%5Csqrt%5B3%5D%7B4%5E3%20%5Ctimes%203%20%5Ctimes%20%28x%5E5%29%5E3%20%5Ctimes%20x%7D%20)
![= 4x^5\sqrt[3]{3x}](https://tex.z-dn.net/?f=%20%3D%204x%5E5%5Csqrt%5B3%5D%7B3x%7D%20)
