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JulijaS [17]
2 years ago
5

Which theorem or postulate can be used to prove ΔRPQ ≅ ΔRST? Given R is the midpoint of QT and QT bisects PS at R.

Mathematics
2 answers:
liq [111]2 years ago
4 0

Answer:

SSS

If this answer is correct, please mark brainliest.

nikklg [1K]2 years ago
3 0

Answer:

<h2>C. SAS</h2>

Step-by-step explanation:

The graph of this problem is attached. There you can observe that we demonstrate the congruence using SAS postulate, which is Side-Angle-Side.

This is the postulate we should use because the mid point divides in equal parts by definition, that means, sides RP and RS are congruent, and sides QR and TR are congruent. In addition, angles QRP and TRS are congruent, because they are vertical angle.

So, we have Side-Angle-Side as congruent parts. Therefore, the postulate we have to use is SAS, option C.

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Answer:

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Step-by-step explanation:

Please write 8x^2 - 48x = -104, with " ^ " indicating exponentiation.  Thanks.

This sounds like a perfect example of "completing the square."

First, factor 8x^2 - 48x = -104:  8(x^2 - 6x = -13).

If we focus SOLELY on x^2 - 6x = -13, it's just a little easier to "complete the square."  Take half of the coefficient of x (which here is -6), and square that result (which here is (-3)^2, or 9.  Now add 9 both sides of x^2 - 6x = -13:

x^2 - 6x + 9 = -13 + 9.  Note:  The "blank" in the problem statement is 9.  

We could go ahead and solve this, tho' we weren't asked to do so.  Rewrite x^2 - 6x + 9 as (x - 3)^2:

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Answer:

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Step-by-step explanation:

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