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yKpoI14uk [10]
2 years ago
14

Describe any domain restrictions that make sense for each of these scenarios: The price of a stock fluctuates several times thro

ughout the year as a function of time. A ball is hit into the air by a baseball player, rises until it reaches its highest point, and then falls into left field. The volume of a spherical balloon increases as the balloon is blown up and decreases as air is let out of it.
Mathematics
2 answers:
mrs_skeptik [129]2 years ago
8 0

Answer:

  • a) Restriction: days of the year (a discrete time)

  • b) The time the ball is on the air: t = 0, until the balls touchs the ground (any real value from t = 0 to t when the ball hits the ground)

  • c) Any positive real value: x ≥ 0

Explanation:

The <em>domain </em>is the set of elements that can be inputs of the <em>function</em>.

<u><em>1. The price of a stock fluctuates several times throughout the year as a function of time.</em></u>

The input variable is the time through out the year.

If you assume that the fluctuaion is recorded once a day, and not every second, the logical assumption is that the time is a day of the year.

Thus, the restricion is the days of the year.

You could represent them in different forms, like DD/MM/YY, or even as a number from 1 to 365 if it covers just one year.

<u><em></em></u>

<u><em>2. A ball is hit into the air by a baseball player, rises until it reaches its highest point, and then falls into left field.</em></u>

The domain is the time the ball is on the air, which may be any real value from t = 0, until the balls touchs the ground.

It is not restricted to integer numbers.

<u><em>3. The volume of a spherical balloon increases as the balloon is blown up and decreases as air is let out of it.</em></u>

The inputs of the function are amounts of air, which may be measured as number of moles.

The number of moles can be any real value equal or greater than zero.

Thus, the domain is the positive real values x ≥ 0.

nydimaria [60]2 years ago
5 0

Answer:

A.) Time is bounded below by zero, or by whatever time the stock price begins to be tracked (the beginning of January, for example), because it doesn’t make sense to have negative time.

B.) Again, time can’t be negative, so the domain is bounded below by zero. Since the height also can’t be negative, the domain is bounded above by the time when the ball hits the ground.

C.) The radius of the balloon is bounded below, because the balloon won’t continue to get smaller once all the air is removed. The radius is also bounded above because at some point the balloon can’t be blown up any more or it will pop.

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Area of a square =

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5 0
1 year ago
A pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm, and 96 cm but does not resonate at any wave
erma4kov [3.2K]

Answer:

A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:

A. closed at both ends

B. open at one end and closed at one end

C. open at both ends.

D. we cannot tell because we do not know the frequency of the sound.

The right choice is:

B. open at one end and closed at one end .

Step-by-step explanation:

Given:

Length of the pipe, L = 120 cm

Its wavelength \lambda_1 = 480 cm

                         \lambda_2 = 160 cm and \lambda_3 = 96 cm

We have to find whether the pipe is open,closed or open-closed or none.

Note:

  • The fundamental wavelength of a pipe which is open at both ends is 2L.
  • The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.

So,

The fundamental wavelength:

⇒ 4L=4(120)=480\ cm

It seems that the pipe is open at one end and closed at one end.

Now lets check with the subsequent wavelengths.

For one side open and one side closed pipe:

An odd-integer number of quarter wavelength have to fit into the tube of length L.

⇒  \lambda_2=\frac{4L}{3}                                   ⇒  \lambda_3=\frac{4L}{5}

⇒ \lambda_2=\frac{4(120)}{3}                              ⇒  \lambda_3=\frac{4(120)}{5}

⇒ \lambda_2=\frac{480}{3}                                  ⇒  \lambda_3=\frac{480}{5}

⇒ \lambda_2=160\ cm                           ⇒   \lambda_3=96\ cm  

So the pipe is open at one end and closed at one end .

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2 years ago
he temperature measured in Kelvin (K) is the temperature measured in Celsius (C) increased by 273.15. This can be modeled by the
PIT_PIT [208]
We have that
<span>K = C + 273.15
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subtract 273.15 both sides
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the answer is
</span>C=K-273.15<span>


</span>
5 0
2 years ago
Read 2 more answers
To evaluate the effect of a treatment, a sample of n=8 is obtained from a population with a mean of μ=40 , and the treatment is
Westkost [7]

Answer:

Step-by-step explanation:

a)

Test statistic:

t=\frac{35-40}{\sqrt{\frac{32}{8} } }

t=-2.5

df=8-1=7

critical, t ,values=+/-2.365

here test statistic lie in rejection region,that why null hypothesis fails  

so Yes, its significant.

b)

Test statistic:

t=\frac{35-40}{\sqrt{\frac{72}{8} } }

t=-1.67

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critical, t ,values=+/-2.365

c)

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Zarrin [17]

22% liked neither.

Step-by-step explanation:

Given,

64% liked pop music.

52% liked rap music.

38% liked both type of music.

To find out the percentage of those liked neither.

Now,

Let, total number of student = 100

Number of students liked pop = 64

Number of students liked rap = 52

Number of students liked both = 38

So,

Number of students who liked only pop = 64-38 = 26

Number of students who liked only rap = 52-38 = 14

Hence,

Number of students who liked neither = 100 - (26+14+38) = 22

22% liked neither.

6 0
2 years ago
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