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Dmitry_Shevchenko [17]
2 years ago
9

What is the value of b in the equation below? StartFraction 5 Superscript 6 Over 5 squared EndFraction = a Superscript b

Mathematics
2 answers:
Margaret [11]2 years ago
4 0

Answer:

B-4

Step-by-step explanation:

Alexus [3.1K]2 years ago
3 0

Answer:

The answer is D=8

Step-by-step explanation:

Just took the test

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Can someone help me with this
Anvisha [2.4K]

Answer:

D. \frac{{7}^{11} }{ {4}^{11} }

Step-by-step explanation:

( \frac{7}{4}) {}^{11} = \frac{7 {}^{11} }{4 {}^{11} }

Since we are multiplying an exponential number to a fraction the answer is going to be

\frac{7 {}^{11} }{4 {}^{11} }

Hope this helps ❤❤❤ ;)

7 0
2 years ago
Read 2 more answers
Eddy's yard is 12 feet wide and 20 feet long. It is covered with grass.
Luba_88 [7]

Answer:

The answer is 32

Step-by-step explanation:

12 plus 20

8 0
2 years ago
Rearrange the following steps in the correct order to locate the last occurrence of the smallest element in a finite list of int
Hatshy [7]

Answer:

procedure last smallest a1,a2,....,an: integers)

min = a1 and location = 1

for i = 2 to n

if min > ai then

min ai and location = i

return location

Step-by-step explanation:

The first step is to define the function or procedure last_smallest; This is done by this line

procedure last smallest a1,a2,....,an: integers)

The next step is to initialize two variables to 1; The first variable is the min which represents minimum while the second is location, which represents its location

min = a1 and location = 1

The next is to iterate from the second element to the last

for i = 2 to n

This line checks for the smallest element; if the following conditional statement returns true, then:->

if min > ai then

->It assigns appropriate values to min and location

min ai and location = i

The last step returns the assigned location of the element

return location

5 0
2 years ago
The number 2A5A0A2 is divisible by 99. What is the digit A
ludmilkaskok [199]

Answer:

A = 3

2A5A0A2 = 2353032

Step-by-step explanation:

Given:

2A5A0A2 is divisible by 9

2A5A0A2 can be divisible by 99 if the sum of the digits can be divided by 9

Digits A is between 0 to 9

2 + A + 5 + A + 0 + A + 2 = 9x

Where,

x = multiples of 9

9 + 3A = 9x

Make A the subject

A = (9x - 9) / 3

When x = 0

A = {9(0) - 9} / 3

= (0 - 9) /3

= -9/3

= -3

When x = 1

A = (9x - 9) / 3

= 9(1) - 9 /3

= 9-9/3

=0/3

A = 0

When x = 2

A = (9x - 9) / 3

= 9(2) -9 / 3

= 18-9/3

= 9/3

A = 3

When x = 3

A = (9x - 9) / 3

= 9(3) - 9 / 3

=27 - 9 /3

= 18/3

A = 6

When x = 4

A = (9x - 9) / 3

= 9(4) -9 /3

= 36-9/3

= 27/3

= 9

Recall, Digits A is between 0 to 9

Substituting A = 0

2050002 ÷ 99

= 20707.09

Substituting A = 3

2A5A0A2

2353032 ÷ 99

= 23,768

Substituting A = 6

2A5A0A2

2656062 ÷ 99

= 26,838.91

Substituting A = 9

2A5A0A2

2959092 ÷ 99

= 29,889.82

Therefore, the only A digit that will not give a decimal number when divided by 9 is 3

A = 3

4 0
2 years ago
Using the following production tally, determine how many total mousetraps were produced during a shift: Quantity per package: 60
timofeeve [1]
The total number of packages completed was 41 and with 60 moustraps per package so 41 x 60 = 2460. Of these, 52 traps were from the previous shift and 34 were rejects so 2460-52-34 = 2374 produced + 24 in the last unsealed package = 2374 +24 = 2398.
3 0
2 years ago
Read 2 more answers
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