Answer:
Answer in explanation
Step-by-step explanation:
In this question, we would be examining the validity of some statements on the number π(pi)
π Is a whole number?
This is wrong, π is a fraction of 22 to 7 parts I.e 22/7
π Is double the radius?
This is wrong. It is the diameter that is double the radius
π Is approximately 3.14?
This is correct to an extent. The actual value in decimal is around 3.142857142857143 which makes the 3.14 somehow correct
π represents the ratio of the circumference of the circle to the diameter?
This is correct.
Mathematically, circumference C = π * diameter D
Hence C/D = π
π Is approximately 22/7?
This is correct. This is the ratio used for π
First, using the order of operations(PEMDAS), you would solve what is inside the parenthesis.
<span>(8.218 + 9.93) + (17.782 + 0.07)
(</span>18.148) + (17.852)
18.148 + 17.852
Now, all you would have to do is add the two sums.
18.148 + 17.852 = <span>36
</span>
The answer would be 36.
I hope this helps!
6 ones 7 hundredths -2.3
We make a place chart for 6 ones 7 hundredths. We write 0 in the remaining place value.
Hundred tens Ones point tenths hundredths thousandths
0 0 6 . 0 7 0
6 one 7 hundredths is 6.07
Now subtract 2.3 from 6.07
6.07 - 2.3 = 3.77
Answer : 3.77
In this case, we will use our Pythagorean Theorem.
a = 84
b = 13
c = x

Thus,
x = 85.
Answer:

Step-by-step explanation:
For the random variable
we define the possible values for this variable on this case
. We know that we have 2 defective transistors so then we have 5C2 (where C means combinatory) ways to select or permute the transistors in order to detect the first defective:

We want the first detective transistor on the ath place, so then the first a-1 places are non defective transistors, so then we can define the probability for the random variable
like this:

For the distribution of
we need to take in count that we are finding a conditional distribution.
given
, for this case we see that
, so then exist
ways to reorder the remaining transistors. And if we want b additional steps to obtain a second defective transistor we have the following probability defined:

And if we want to find the joint probability we just need to do this:

And if we multiply the probabilities founded we got:
