Rashal is adding the expression below. Negative 3 + left-bracket (negative 7) + (negative 6) right-bracket First, he rewrites th
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Let numbers of books be 'b' and numbers of CDs be 'c'
We can set up two equations:
Equation [1] ⇒
Equation [2] ⇒
We are solving for the number of books and the number of CDs bought
When we have two equations in terms of two different variables;
and 
, that we need to solve, then this becomes a simultaneous equation problem.
First, rearrange Equation [1] to make either or the subject:
Then we substitute into Equation [2]
Now we know the value of which is , substitute this value into we have 
Answer:
Numbers of books = 13
Numbers of CDs = 7
We can set up two equations:
Equation [1] ⇒
Equation [2] ⇒
We are solving for the number of books and the number of CDs bought
When we have two equations in terms of two different variables;
First, rearrange Equation [1] to make either
Then we substitute
Now we know the value of
Answer:
Numbers of books = 13
Numbers of CDs = 7
From the table, the speed of Corinne is given by
From the graph, the speed of Aretha is given by
The distance from the starting point of Corinne at any time t is given by D = 0.125t while the distance from the starting point of Aretha at any time t is given by D = 3.5 + 0.1t
Let t be the number of minutes after the start of the race when Corinne catchs Aretha, then
0.125t = 3.5 + 0.1t
0.025t = 3.5
t = 3.5 / 0.025 = 140
Therefore, the number of <span>minutes after the start of the race that Corinne will catch Aretha</span> is 140 minutes.
From the graph, the speed of Aretha is given by
The distance from the starting point of Corinne at any time t is given by D = 0.125t while the distance from the starting point of Aretha at any time t is given by D = 3.5 + 0.1t
Let t be the number of minutes after the start of the race when Corinne catchs Aretha, then
0.125t = 3.5 + 0.1t
0.025t = 3.5
t = 3.5 / 0.025 = 140
Therefore, the number of <span>minutes after the start of the race that Corinne will catch Aretha</span> is 140 minutes.