Type the correct answer in the box. Round your answer to two decimal places.

The speed limit on a road is 60 mph. The actual speeds of cars are measured and found to be normally distributed with a mean val

Vladimir79 [104]

Answer: 8.1%

Step-by-step explanation:

Given : $\mu=63$

$\sigma=5$

Let x be the random variable that represents the actual speeds of cars.

The speed limit on a road is 60 mph.

Using formula , $z=\dfrac{x-\mu}{\sigma}$ , we have for x= 60+10=70

$\dfrac{70-63}{5}=1.4$

Using z-table for right-tailed test value, The probability of cars exceed the speed limit by more than 10 mph will be

$P(x>70)=P(z>1.4)=0.0807567\approx0.081=8.1\%$

Hence, the percentage of cars exceed the speed limit by more than 10 mph is 8.1%.

6 0

2 years ago

Your utility company charges 13 cents per kilowatt-hour of electricity. What is the daily cost of keeping lit a 75 watt light bu

Tresset [83]

we know that

$1 Kw=1000 w$

The company charges $13$ cents per kilowatt-hour of electricity

$13 cents=0.13 dollars\\\\ 75w=\frac{75}{1000} kw\\\\ 15w=\frac{15}{1000} kw$

Step $1$

Find the cost for the light bulb

a) in one day

$\frac{75}{1000} *12=0.9\ kw\ hour$

$Cost=0.13*0.9$

Cost=$ $0.117$

b) In a year

$\frac{75}{1000} *12=0.9\ kw\ hour$

$0.9*365=328.5\ kw\ hour$

$Cost=0.13*328.5$

Cost=$ $42.71$

Step $2$

Find the cost for the led bulb

a) in one day

$\frac{15}{1000} *12=0.18\ kw\ hour$

$Cost=0.13*0.18$

Cost=$ $0.0234$

b) In a year

$\frac{15}{1000} *12=0.18\ kw\ hour$

$0.18*365=65.7\ kw\ hour$

$Cost=0.13*65.7$

Cost=$ $8.54$

Step $3$

Find the difference in cost

$Save=42.71-8.54\\ Save=34.17 dollars$

therefore

the answer is

$34.17 dollars$

3 0

2 years ago

Read 2 more answers

Fred buys a video game disk for $4 there was a discount of 20% what is the sales price please show work

polet [3.4K]

multiply the price by the discount then subtract the answer from the price

4 * 0.20 = 0.80

4-0.80 = 3.20

sale price is $3.20

8 0

2 years ago

Roberto wants to display his 18 sports cards in an album. Some pages hold 2 cards and others hold 3 cards. How many different wa

Ratling [72]

<span>65 = number of different arrangements of 2 and 3 card pages such that the total number of card slots equals 18. 416,154,290,872,320,000 = number of different ways of arranging 18 cards on the above 65 different arrangements of page sizes. ===== This is a rather badly worded question in that some assumptions aren't mentioned. The assumptions being: 1. The card's are not interchangeable. So number of possible permutations of the 18 cards is 18!. 2. That all of the pages must be filled. Since the least common multiple of 2 and 3 is 6, that means that 2 pages of 3 cards can only be interchanged with 3 pages of 2 cards. So with that said, we have the following configurations. 6x3 card pages. Only 1 possible configuration. 4x3 cards and 3x2 cards. These pages can be arranged in 7!/4!3! = 35 different ways. 2x3 cards and 6x2 cards. These pages can be arranged in 8!/2!6! = 28 ways 9x2 card pages. These can only be arranged in 1 way. So the total number of possible pages and the orders in which that they can be arranged is 1+35+28+1 = 65 possible combinations. Now for each of those 65 possible ways of placing 2 and 3 card pages such that the total number of card spaces is 18 has to be multiplied by the number of possible ways to arrange 18 cards which is 18! = 6402373705728000. So the total amount of arranging those cards is 6402373705728000 * 65 = 416,154,290,872,320,000</span>

7 0

2 years ago

Marvin find doubles facts, such as 4+4 and 1+1,on the addition table. He colors each sum. What pattern does Marvin make when he

adoni [48]

4+4=8 so 1+1=2 that the answer

8 0

2 years ago

Read 2 more answers