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Umnica [9.8K]
1 year ago
5

I am a multiple of 60 I am between 400 and 600 I am 40 away from a multiple of 100 who am I

Mathematics
1 answer:
EleoNora [17]1 year ago
8 0

Answer:

540 is the answer i think

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If a person invests $220 at 7% annual interest, find the approximate value of the investment at the end of 10 years.
frez [133]

\bf ~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$220\\ r=rate\to 7\%\to \frac{7}{100}\dotfill &0.07\\ t=years\dotfill &10 \end{cases} \\\\\\ A=220[1+(0.07)(10)]\implies A=220(1.7)\implies A=374

5 0
1 year ago
Read 2 more answers
How do i evaluate 256 1/4 .? this is algebra 2.
Mariulka [41]
Look it up on photomath
6 0
2 years ago
Problem 5 (4+4+4=12) We roll two fair 6-sided dice. Each one of the 36 possible outcomes is assumed to be equally likely. 1) Fin
tekilochka [14]

Answer:

1

p(b) =  \frac{1}{6}

2

p(k) =  \frac{1}{3}

3

P(a) =  \frac{1}{3}

Step-by-step explanation:

Generally when two fair 6-sided dice is rolled the doubles are

(1 1) , ( 2 2) , (3 3) , (4 4) , ( 5 5 ), (6 6)

The total outcome of doubles is N = 6

The total outcome of the rolling the two fair 6-sided dice is

n = 36

Generally the probability that doubles (i.e., having an equal number on the two dice) were rolled is mathematically evaluated as

p(b) =  \frac{N}{n}

p(b) =  \frac{6}{36}

p(b) =  \frac{1}{6}

Generally when two fair 6-sided dice is rolled the outcome whose sum is 4 or less is

(1, 1), (1, 2), (1, 3), (2, 1), (2, 2), (3, 1)

Looking at this outcome we see that there are two doubles present

So

The conditional probability that doubles were rolled is mathematically represented as

p(k) =  \frac{2}{6}

p(k) =  \frac{1}{3}

Generally when two fair 6-sided dice is rolled the number of outcomes that would land on different numbers is L = 30

And the number of outcomes that at least one die is a 1 is W = 10

So

The conditional probability that at least one die is a 1 is mathematically represented as

P(a) =  \frac{W}{L}

=> P(a) =  \frac{10}{30}

=> P(a) =  \frac{1}{3}

3 0
1 year ago
Suppose that 3% of all athletes are using the endurance-enhancing hormone EPO (you should be able to simply compute the percenta
trapecia [35]

Answer:

Step-by-step explanation:

So there is a 3% probability that an athlete is using EPO .

The probability of showing positive on a test when you've used it is 0.99.

3% x 0.99= 2.97%

The probability of a positive result without EPO is 0.1

97% x 0,1 = 9,7 %

My guess is that 2.97% + 9,7% = 12.67% or 0.1267.

I don't know i may be wrong because you've put as an answer 0.0297 but if you like you may take only the first part of the answer.

6 0
2 years ago
Adriana writes the equation y = 2x + 4 to represent a line on a graph. Henry writes an equation that has a y-intercept that is 1
grigory [225]

Answer:

it is y = 2x + 3

Step-by-step explanation:

i just took the test

3 0
1 year ago
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