(a) (3a⁴)³ = 3³a³*⁴ = 9a^12
(b) (2m³)⁶ = 2⁶m⁶*³ = 64m^18
(c) (7p⁵)² = 7²p²*⁵ = 49p^10
(d) (10k²)⁴ = 10⁴k⁴*² = 10000k⁸
(e) (5t^11)³ = 5³t^11*³ = 125t³³
(f) (x³y²)⁵ = x⁵*³y⁵*² = x^15y^10
(g)(m⁴n⁶)³ = m³*⁴n³*⁶ = m^12n^18
(h) (p⁷q³)⁴ = p⁴*⁷q⁴*³ = p²⁸q^12
(i) (a⁴b^10)² = a²*⁴b²*^10 = a⁸b^20
(j) (2x⁵y²)³ = 2³x³*⁵y³*² = 8x^15y⁶
(k) (3x⁷y⁴)³ = 3³x³*⁷y³*⁴ =27x^21y^12
(l) (5p²q⁴)³ = 5³p³*²q³*⁴ =125p⁶q^12
The given polynomial is
As this is a fourth degree polynomial, we can not directly use any formula, So here we will use hit and trial method
check whether x=-1 is a zero of the polynomial or not
Hence x=-1 is not a zero.
Now check whether x=-2 is a zero of the polynomial or not
Hence x=-2 is a zero of the polynomial.
Hence we can re-write the polynomial as
Hence the required binomial is (x+2)
Answer: 10 hours
Explanation:
1) Fernando's earnings:
10 + 4h ← 10 is a fix charge, h is the number of hours and 4 is the rate per hour
2) Fernando's savings
0.30 (10 + 4h) ← 30% = 30 / 100 = 0.3
3 + 1.2h ← distributive property
3) Brenna's earnings
6h ← h is the number of hours, 6 is the rate per hour
4) Brenna's savings
0.25(6h) ← 25% = 25/100 = 0.25
1.5h ←0.25 × 6 = 1.5
5) Equal savings
3 + 1.2h = 1.5h
1.5th- 1.2h = 3 ← transpose terms
0.3h = 3 ← combine like terms
h = 3 / 0.3 = 10 ← divide by 0.3
Answer: h = 10
