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Umnica [9.8K]
1 year ago
10

50 POINTS [GEOMETRY] If m∠DEG= 5x - 4 m∠GEF=7x - 8 m∠DEH= 9y + 5 find the values of x and y

Mathematics
2 answers:
patriot [66]1 year ago
8 0

we are given

DEF is a line

so, sum of angles must be 180

angle(DEG)+angle(GEF)=180

now, we can plug values

5x-4+7x-8=180

12x-12=180

12x=192

x=16.........Answer

vertically opposite angle must be equal

angle(GEF)=angle(DEH)

now, we can plug values

9y+5=7x-8

now, we can plug x=16

9y+5=7*16-8

9y+5=104

9y=99

y=11...................Answer


Roman55 [17]1 year ago
5 0

Answer:  x=16   and y=11

Step-by-step explanation:

In the given figure , we two lines GH and DF intersecting each other at E.

m∠DEG= 5x - 4 ,  m∠GEF=7x - 8,  m∠DEH= 9y + 5   (1)

Since ∠DEG and ∠GEF lies on line DF.

Then, m∠DEG + m∠GEF=180°            [Linear pair]

\Rightarrow\ 5x - 4+7x - 8=180       (from (1))

\Rightarrow\ 12x-12=180

\Rightarrow\ 12x=180+12

\Rightarrow\ 12x=192

\Rightarrow\ x=\dfrac{192}{12}=16

Then, m∠GEF=7x - 8= 7(16)-8=104°       (2)

Also, ∠GEF and ∠DEH are vertical opposite angles.

And measure of vertical angles are equal.

∴  m∠GEF= m∠DEH

104=9y+5\ \ \text{[Using (1) and (2) ]}\\\\\Rightarrow\ 9y=104-5\\\\\Rightarrow\ 9y=99\\\\\Rightarrow\ y=11

Hence, the values of x and y  are 16 and 11 respectively.

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One year ago, you purchased 600 shares of stock for $14 a share. the stock pays $.41 a share in dividends each year. today, you
alukav5142 [94]
If you paid $14 for 600, you paid:

600 * 14 = $8,400.00

If you sold them for $15.30 a share, you made:

600 * 15.30 = $9,180

9,180 - 8,400 = $780

The return on the investment being $780

Very very safe investment and not worth it.
5 0
2 years ago
Use mental math. A resort has 380 rooms with space for 6 people. Estimate the greatest number of people who could be in these ro
Olin [163]

Answer:

6 people

Step-by-step explanation:

Since the resort has 380 rooms with space for 6 people, only 6 people can be in these rooms at the same time.

Note: It was not said that each room has space for 6 people but the hotel has space for 6 people

Irrespective of the number of rooms available, the space limit is 6, hence not more than 6 people can be accommodated.

5 0
2 years ago
A jet flies 425 km from Ottawa to Québec at rate v + 60. On the return flight, the
Marina CMI [18]

Answer:

a. \frac{- 42,500}{(v + 60)(v - 40)}

Step-by-step Explanation:

Given:

Distance Ottawa to Québec = 425 km

Initial flight rate = v + 60

Return flight rate = v - 40

t = \frac{d}{r}

Required:

Flight times difference of the initial and return flights

Solution:

=>Flight time of the initial flight:

t = \frac{d}{r}

t = \frac{425}{v + 60}

=>Flight time of the return flight:

t = \frac{425}{v - 40}

=>Difference in flight times:

\frac{425}{v + 60} - \frac{425}{v - 40}

\frac{425(v - 40) -425(v + 60)}{(v + 60)(v - 40)}

\frac{425(v) - 425(40) -425(v) -425(+60)}{(v + 60)(v - 40)}

\frac{425v - 17000 -425v - 25500}{(v + 60)(v - 40)}

\frac{425v - 425v - 17000 - 25500}{(v + 60)(v - 40)}

\frac{- 42,500}{(v + 60)(v - 40)}

3 0
2 years ago
Find the values of k for which the line y=1-2kx does not meet the curve y=9x²-(3k+1)x+5
Lilit [14]

Let's equate the two given functions and attempt to solve for x:

y = 1 -2kx = y = 9x^2 -(3k+1)x + 5

Eliminating y, 1 -2kx = 9x^2 -(3k+1)x + 5

Rearranging terms in descending order by powers of x:

0 = 9x^2 - (3k+1)x + 2kx + 5 - 1 , or

0 = 9x^2 - kx - x + 4

This is a quadratic equation with coefficients a = 9, b = -(k+1) and c = 4.

For certain k, not yet known, solutions exist. Solutions here implies points at which the two curves intersect.

k+1 plus or minus sqrt( [-(k+1)]^2 - 4(9)(4) )

x = -----------------------------------------------------------------

2(9)

The discriminant is k^2 + 2k + 1 - 144, or k^2 + 2k - 143.

If the discriminant is > 0, there are two real, unequal roots. We don't want this, since we're interested in finding k value(s) for which there's no solution.

If the discr. is = 0, there are two real, equal roots. Again, we don't want this.

If the discr. is < 0, there are no real roots. This is the case that interests us.

So our final task is to determine the k values for which the discr. is < 0:

Determine the k value(s) for which the discriminant, k^2 + 2k - 143, is 0.

This k^2 + 2k - 143 factors as follows: (k-11)(k+13), and when set = to 0, results in k: {-13,11}.

Set up intervals on the number line: (-infinity, - 13), (-13, 11) and (11, infinity).

Choosing a test number from each interval, determine the interval or intervals on which the discriminant is negative:

Case 1: k = -15; the discriminant (k^2 + 2k - 143) is (-15)^2 + 2(-15) - 143 = +52. Reject this interval

Case 2: k = 0; the discriminant is then 0 + 0 - 143 (negative); thus, the discriminant is negative on the interval (-13,11).

Case 3: k = 20; the discriminant is positive. Reject this interval.

Summary: The curves do not intersect on the interval (-13,11).

4 0
2 years ago
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Gavin wrote the equation p = StartFraction 3 (s + 100) Over 4 EndFraction to represent p, the profit he makes from s sales in hi
Degger [83]

Given the equation p = 3(s + 100)/4 

Where,

p = profit made

s = sales 

Solving for s from the given equation

p = 3(s + 100)/4

Multiply both sides by 4

4p = 3(s + 100)

4p = 3s + 300

Subtract 300 from both sides of the equation

4p – 300 = 3s

Same as, 3s = 4p – 300

s = (4p – 300)/3 

OR, s = 4p/3 – 100 

If any of these two is in the options, it’s the right answer.

4 0
1 year ago
Read 2 more answers
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