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Mashcka [7]
2 years ago
11

Gavin wrote the equation p = StartFraction 3 (s + 100) Over 4 EndFraction to represent p, the profit he makes from s sales in hi

s lawn-mowing business. Which equation is solved for s? s = StartFraction p minus 100 Over 3 EndFraction s = StartFraction 4 p minus 300 Over 3 EndFraction s = StartFraction 4 p Over 300 EndFraction s = StartFraction 400 p Over 3 EndFraction
Mathematics
2 answers:
Degger [83]2 years ago
4 0

Given the equation p = 3(s + 100)/4 

Where,

p = profit made

s = sales 

Solving for s from the given equation

p = 3(s + 100)/4

Multiply both sides by 4

4p = 3(s + 100)

4p = 3s + 300

Subtract 300 from both sides of the equation

4p – 300 = 3s

Same as, 3s = 4p – 300

s = (4p – 300)/3 

OR, s = 4p/3 – 100 

If any of these two is in the options, it’s the right answer.

adell [148]2 years ago
3 0

Answer:

the answer is b

Step-by-step explanation:

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Answer:

A. 0.006

B. 0.02

C. They are dependent

Step-by-step explanation:

Given

P(A) = 0.01 ---- The probability that A faile

P(B) = 0.03 --- The probability that B fails

P(B|A) = 0.06 ---- The probability that B will fail if A fails

A. What is the probability of an accidental missile launch?

If an accidental missile is launched, then this means we're asked to calculate the probability that A fails and B fails

This is given by P(A and B)

The expression,

P(B|A)=P(A and B)/P(A) will be used to solve this question.

Substitute in the values

0.06 = P(A and B) / 0.01 ---- Make P(A and B) the subject of formula

P(A and B) = 0.01 * 0.06

P(A and B) = 0.006

B. What is the probability that A will fail if B has failed?

Here, we're to calculate P(A|B)

This is calculated by

P(A|B)=P(A and B)/P(B)

Where P(A and B) = 0.006

Substitute in the values

P(A|B) = 0.006 / 0.03

P(A|B) = 0.02

C. Are the events "A fails" and ''B fails" statistically independent?

If the occurrence of event A fails does not affect the occurrence of the event B fails and vice versa then they are independent.

Meaning that if P(B|A)=P(B) or P(A|B)=P(A) they are independent.

But P(A|B) = 0.02 and P(A) = 0?01

Since the values are not the same

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7 0
2 years ago
Suppose a research paper states that the distribution of the daily sea-ice advance/retreat from each sensor is similar and is ap
Luda [366]

Answer:

The value of the parameter is λ is 0.03553357

Step-by-step explanation:

Consider the provided function.

f(x) = 0.5\lambda e^{-\lambda |x|} for −∞ < x < ∞.

It is given that standard deviation is given as 39.8 km.

Now we need to calculate the value of parameter λ.

The general formula for the probability density function of the double exponential distribution is: f(x)=\frac{e^{-|\frac{x-\mu}{\beta}|}}{2\beta}

Where μ is the location parameter and β is the scale parameter.

Compare the provided equation with the above formula we get.

\lambda=\frac{1}{\beta} and μ = 0.

Standard deviation = √2β

S.D=\sqrt{2} \beta\\\beta=\frac{39.8}{\sqrt{2}}\\\beta=28.1424

Now substitute the value of β in \lambda=\frac{1}{\beta}.

\lambda=\frac{1}{28.1424}=0.03553357

Hence, the value of the parameter is λ is 0.03553357

3 0
2 years ago
A simple random sample of 100 concert tickets was drawn from a normal population. The mean and standard deviation of the sample
alexandr402 [8]

Answer:

We accept the null hypothesis and the population mean is $120.

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 100

Sample mean, \bar{x} = $120

Alpha, α = 0.01

Sample standard deviation, s = $25

First, we design the null and the alternate hypothesis

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We use two-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = -2.0              

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p-value two tail= 0.048

Conclusion:

Since the p-value for two tailed test is greater than the significance level, we fail to reject the null hypothesis and accept it.

Thus, the population mean is $120.

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Sammy wrote the following proof. What did he do wrong?
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