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2 years ago

Dolores bought 15 party hats priced at $0.75 each and 15 noisemakers priced at $1.25 each. How much did Dolores spend in all?

Mathematics

2 answers:

Ludmilka [50]2 years ago

8 0

She spends 30 dollars

Naddik [55]2 years ago

4 0

The answer is 30$!!

i hope this helps and have a wonderful day!

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W = 3x + 7y solve for y

mario62 [17]

Answer:

The value of the equation $y=\frac{W-3x}{7}$ .

Step-by-step explanation:

Consider the provided equation.

$W = 3x + 7y$

We need to solve the provided equation for y.

Subtract 3x from both side.

$W-3x= 3x-3x+ 7y$

$W-3x=7y$

Divide both sides by 7.

$\frac{7y}{7}=\frac{W-3x}{7}$

$y=\frac{W-3x}{7}$

Hence, the value of the equation is $y=\frac{W-3x}{7}$ .

8 0

1 year ago

If a cow has a mass of 9×102 kilograms, and a blue whale has a mass of 1.8×105 kilograms, which of these statements is true?

lana66690 [7]

Answer:

The mass of the Blue whale is 200 times the mass of the cow

Step-by-step explanation:

Given

Mass of Cow = 9 * 10² kg

Mass of Blue Whale = 1.8 * 10⁵ kg

Required

Determine the relationship between both weights

Represent the mass of the cow with C and the mass of the whale with B

$C = 9 * 10^2kg$

$C = 9 *100kg$

$C = 900kg$

$B = 1.8 * 10^5kg$

$B = 1.8 * 100000kg$

$B = 180000kg$

Divide the bigger weight by the smaller weight

$\frac{B}{C} = \frac{180000kg}{900kg}$

$\frac{B}{C} = \frac{180000}{900}$

$\frac{B}{C} = {200}{}$

Multiply both sides by C

$C * \frac{B}{C} = {200}{} * C$

$B = {200}{} * C$

$B = 200}C$

<em>From the expression above, it can be concluded that the mass of the Blue whale is 200 times the mass of the cow</em>

7 0

1 year ago

A food company originally sells cereal in boxes with dimensions 25 cm by 14 cm by 10 cm. To make more profit, the company decrea

hjlf

Answer:

1.75 cm

Step-by-step explanation:

We are given that the dimensions of the box as 25 cm by 14 cm by 10 cm.

Now, to increase the profit, the dimensions of the box by 'x' cm.

Thus, the new dimensions are (25-x) cm by (14-x) cm by (10-x) cm.

Further, it is given that the volume of the new box is 2,208 $cm^{3}$

As, Volume of the box = Length × Breadth × Height

i.e. 2208 = (25-x) × (14-x) × (10-x)

i.e. $2208 = (25-x) \times (140-24x-x^{2})$

i.e. $2208=x^{3}-x^{2}-740x+3500$

i.e. $x^{3}-x^{2}-740x+1292=0$

On solving this cubic equations, we get that, the solutions are x = 27.6, x = 1.75 and x = 26.8.

Since, the dimensions 25 cm by 14 cm by 10 cm are reduced by x cm.

Thus, if x = 27.6 or x = 26.8, then (10-x) = -17.6 or -16.8, which cannot be possible. So, x = 1.75 cm.

Hence, the dimensions were decreased by 1.75 cm.

3 0

1 year ago

Weekly demand for a particular item averages 30 units, with a standard deviation of 4. This item is managed with a fixed-order-i

aivan3 [116]

Answer:

(B)93

Explanation:

Since we are using a fixed-order-interval model,

The Amount to Order=Expected Demand During protection Interval+Safety Stock-Amount at Hand

$=d(OI+LT)+z\sigma_{d}\sqrt{OI+LT}-A$

Where:

d=weekly demand

OI=Order Interval

LT=Lead Time

z=Standard Deviation of Desired Service Level

$\sigma_{d}$ =Standard Deviation of weekly Demand

A= Amount at Hand

$=d(OI+LT)+z\sigma_{d}\sqrt{OI+LT}-A$

$[30(3 + 1)] + [1.964*4*\sqrt{3 + 1} - 43$

$= 120 + 15.712 - 43 = 92.7$

4 0

1 year ago

A hotel has 270 units. All rooms are occupied when the hotel changes $90 per day for a room. For every increase of x dollars in

Brut [27]

62 dollars i think tho i'm not very sure, sorry for not knowing exactly but god bless and have a good day/night/week/month/year/life <3

4 0

1 year ago