Answer and Step-by-step explanation:
As it is mentoned in the question
Polygon ABCDE rotates around point F in clockwise direction to create polygon FGHIJ
And as we can see in the figure that
So we conclude that
A = F ⇒ 117°
B = G ⇒ 90°
C = H ⇒ 127°
D = I ⇒ 90°
E = J ⇒ 117°
Therefore this is the answer and the same is to be considered
The response time includes the round-trip signal time plus the robot's travel time.
59 min = 2*(9.5 min) +travel time
59 min -2*(9.5 min) = travel time = 40 min
The speed is distance / travel time
speed = (52.8 m)/(40 min) = 1.32 m/min
The robot's average speed was 1.32 meters per minute.
Answer:
The equation are:
1) h + s = 20
2) 4h = 1s
Step-by-step explanation:
Number of hats Elliott made = h
Number of scarfs Elliott made = s
total number of items Elliott made = 20
h + s = 20 ..[1]
1 hat uses 0.2 kilograms of yarn
1 hat = 0.2 kg of yarn
Then h hats will use = 0.2h kg of yarn
1 scarf uses 0.1 kilograms of yarn
1 scarf= 0.1 kg of yarn
Then s scarfs will use = 0.1s kg of yarn
She wants to twice as much as yarn for scarves for hats:
2 × (0.2h kg of yarn) = 0.1s kg of yarn
0.4h = 0.1s
4h = 1s...[2]
The equation are:
1) h + s = 20
2) 4h = 1s
the
complete question in the attached figure
1) Find the probability that all nine victims would select the same person. You should enter your answer as a decimal, not as a percent. Do not round, as your answer should be a terminating decimal.
P=(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)=0.000000512
2) what is the probability that the first victim picks SOMEONE? ANYONE?
P=(1/5)=0.20 ---------------- > 20%
3) Now let’s look at victim #2. What is the probability that they pick the same person as victim #1?
P=(1/5)*(1/5)=0.04 --------------> 4%
4) Now let’s look at victim #3. What is the probability that they pick the same person as victim #1?
P=(1/5)*(1/5)*(1/5)=0.008 --------------> 0.8%
5) Now let's look at victim #9. What is the probability that they pick the same person as victim #1?
P=(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)=0.000000512
6) Once you find all those probabilities, what rule would apply?
the probability is
given by (1/5)^n
n=number of victims that pick the same person---------> in this problem = 9
P=(1/5)^9= 0.000000512
1) The outcomes for rolling two dice, the sample space, is as follows:
(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)
(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)
There are 36 outcomes in the sample space.
2) The ways to roll an odd sum when rolling two dice are:
(1, 2), (1, 4), (1, 6), (2, 1), (2, 3), (2, 5), (3, 2), (3, 4), (3, 6), (4, 1), (4, 3), (4, 5), (5, 2), (5, 4), (5, 6), (6, 1), (6, 3), (6, 5). There are 18 outcomes in this event.
3) The probability of rolling an odd sum is 18/36 = 1/2 = 0.5
