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grin007 [14]
1 year ago
8

Let x be a random variable representing the amount of sleep each adult in New York City got last night. Consider a sampling dist

ribution of sample means x. (a) As the sample size becomes increasingly large, what distribution does the x distribution approach? uniform distribution sampling distribution normal distribution binomial distribution (b) As the sample size becomes increasingly large, what value will the mean μx of the x distribution approach? μx μ μ/√n μ/n σ (c) What value will the standard deviation σx of the sampling distribution approach? σ/n σx σ/√n μ σ (d) How do the two x distributions for sample size n = 50 and n = 100 compare? (Select all that apply.) The standard deviations are μ / 50 and μ / 100, respectively. The means are the same. The standard deviations are the same. The standard deviations are σ / √50 and σ / √100, respectively. The standard deviations are μ / √50 and μ / √100, respectively. The standard deviations are σ / 50 and σ / 100, respectively.
Mathematics
2 answers:
Sonbull [250]1 year ago
8 0

Answer:

a) As the sample size becomes increasingly large, the distribution approximates a normal distribution.

b) As the sample size becomes increasingly large, the mean of the sampling distribution, μₓ, approach as the population mean, μ.

σₓ

c) The standard deviation of the sampling distribution is given as

σₓ = (σ/√n)

d) Two sampling distributions with Sample size 50 and 100 have standard deviation of sampling distribution of (σ/√50) and (σ/√100) respectively.

Step-by-step explanation:

The Central limit theorem explains that sample distributions obtained from a population distribution (especially normally distributed ones) have distributions that approximate a normal distribution, a mean that is equal to the population mean and a standard deviation of sampling distribution given as the population standard deviation divided by square root of sample size.

a) Just like the Central limit theorem explains, as the sample size becomes increasingly large, the distribution approximates a normal distribution

b) And as the sample size becomes increasingly large, the mean of the sampling distribution, μₓ, approach as the population mean, μ.

c) The standard deviation of the sampling distribution is given as the population standard deviation divided by square root of sample size.

d) Using the formula given in (c) above, the standard deviation of sampling distribution of two sampling distributions with sample size 50 and 100 are (σ/√50) and (σ/√100) respectively.

Hope this Helps!!!

dangina [55]1 year ago
4 0

Answer:

Step-by-step explanation:

Given that X is a random variable representing the amount of sleep each adult in New York City got last night.

a) Normal distribution (by central limit theorem)

b) Sample mean will approach population mean mu

c) the standard deviation σx of the sampling distribution approach to σ/√n

d)  The means are the same.

. The standard deviations are σ / √50 and σ / √100, respectively.

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Answer:

Check Explanation

Step-by-step explanation:

The options to be examined for the wrong one isn't presented, and it wasn't obtainable online, So, I'll exhaustively cover all the common possible answers!

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So, if 5 acres of land is to be divided into 13 sections with equal areas.

Each of the 13 land areas will have an area of (5/13) = 0.385 acre

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Each of the 13 land areas will have an area of (20234.28/13) = 1556.5 m²

1 acre = 43560 ft²

5 acres = 5 × 43560 = 217,800 ft²

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5 acres = 5 × 0.00156 = 0.0078 square miles

Each of the 13 land areas will have an area of (0.0078/13) = 0.0006 square miles.

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Step-by-step explanation:

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