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azamat
1 year ago
6

Information was collected on those who attended the opening of a new movie. The analysis found that 56 percent of the moviegoers

were female, 26 percent were under age 25, and 17 percent were females under the age of 25. Find the probability that a moviegoer is either female or under age 25.
Mathematics
1 answer:
kherson [118]1 year ago
6 0

Answer: 0.65

Step-by-step explanation:

Let A denote that moviegoers were female and B denotes that moviegoers were under age 25.

As per given we have,

P(A)=0.56     P(B)=0.26     P(A∩B)=0.17

Using formula ,

P(A\cup B)=P(A)+P(B)-P(A\cap B)\\\\ P(A\cup B)=0.56+0.26-0.17=0.65

Hence, the probability that a moviegoer is either female or under age 25 = 0.65

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Answer: The correct statements are

The GCF of the coefficients is correct.

The variable c is not common to all terms, so a power of c should not have been factored out.

David applied the distributive property.

Step-by-step explanation:

GCF = Greatest common factor

1) GCF of coefficients : (80,32,48)

80 = 2 × 2 × 2 × 2 × 5

32 = 2 × 2 × 2 × 2 × 2

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GCF of variables :(b^4,b^2,b^4) is b^2

3) GCF of c^3 and c: c is not the GCF of the polynomial. The variable c is not common to all terms, so a power of c should not have been factored out.

4) 80b^4-32b^2c^3+48b^4c

=16b^2(5b^2-2c^3+3b^2c)

David applied the distributive property.

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1 year ago
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Answer:

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Step-by-step explanation:

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Answer:

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That is

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