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Diano4ka-milaya [45]
1 year ago
15

At a local grocery store, apples cost $0.50 each and bananas cost $0.30 each. The expression 0.50x + 0.30y can be used to find t

he cost of buying some apples and bananas. 1. Interpret what the x and y represent in context. 2. What does each term represent? 3. What do each of the coefficients represent?
Mathematics
1 answer:
JulsSmile [24]1 year ago
3 0

(1) x represents the number of apples bought, y represents the number of bananas.

(2) each term represents the total costs of a given fruit, so 0.50x is the total cost of apples and 0.30y is total cost of bananas.

(3) The coefficients are unit prices: coefficient 0.50 is the price of 1 apple, 0.30 is the price of 1 banana.

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Two con terminal angles 3pi/4 negative and positive answer in radians
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Answer:

Negative Coterminal: -5π/4

Positive Coterminal: 11π/4

Step-by-step explanation:

The easiest way to find <em>specific </em>(not infinite) coterminal values is to ±2π. When you subtract 2π, you will get a negative coterminal. When you add 2π, you will get a positive coterminal. Keep in mind though that a tan∅ or cot∅ only needs ±π, not ±2π.

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Galen wrote the statement "If the sum of the digits in a number is divisible by 3, the original number is divisible by 3." Which
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the answer is B. good luck

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2 years ago
Flip two coins 100 times, and record the results of each coin toss in a table like the one below:
monitta

Answer:

1)The theoretical probability that a coin toss results in two heads showing is 25%.

2)The experimental probability that a coin toss results in two heads showing is 44%.

3) The theoretical probability that a coin toss results in two tails showing is 25%.

4) The experimental probability that a coin toss results in two tails showing is 34%.

5) The theoretical probability that a coin toss results in one head and one tail showing is 50%.

6) The experimental probability that a coin toss results in a head and a tail is 22%.

7) The experimental probabilities are slightly different from the theoretical probabilities because the number of experiments is relatively small. As the number of experiments increase, the experimental probabilities will get closer to the theoretical probabilities.

Step-by-step explanation:

Probability:

What you want to happen is the desired outcome.

Everything that can happen iis the total outcomes.

The probability is the division of the number of possible outcomes by the number of total outcomes.

Theoretical Probability:

The results you expect to happen.

Experimental Probability:

The probability determined from the result of an experiment.

1. What is the theoretical probability that a coin toss results in two heads showing?

In each toss, the theoretical  probability that a coin toss results in a head showing is 50%.

So for two coins, the probability is:

P = (0.5)^{2} = 0.25

The theoretical probability that a coin toss results in two heads showing is 25%.

2. What is the experimental probability that a coin toss results in two heads showing?

There were 100 flips, and it resulted in two heads 44 times, so:

P = \frac{44}{100} = 0.44

The experimental probability that a coin toss results in two heads showing is 44%.

3. What is the theoretical probability that a coin toss results in two tails showing?

In each toss, the theoretical  probability that a coin toss results in a tail showing is 50%.

So for two tails, the probability is:

P = (0.5)^{2} = 0.25

The theoretical probability that a coin toss results in two tails showing is 25%.

4. What is the experimental probability that a coin toss results in two tails showing?

There were 100 flips, and it resulted in two tails 34 times, so:

P = \frac{34}{100} = 0.34

The experimental probability that a coin toss results in two tails showing is 34%.

5. What is the theoretical probability that a coin toss results in one head and one tail showing?

In each toss, the theoretical probability that a coin toss results in a tail showing is 50% and in a head showing is 50%.

They can be permutated, as the tail can appear before the head, or the head before the tail. So:

P = p_{2,1}*(0.5)*(0.5) = \frac{2!}{1!}*0.25 = 0.50

The theoretical probability that a coin toss results in one head and one tail showing is 50%.

6. What is the experimental probability that a coin toss results in one head and one tail showing?

There were 100 flips, and it resulted in a head and a tail showing 22 times, so:

P = \frac{22}{100} = 0.22

The experimental probability that a coin toss results in a head and a tail is 22%.

6 0
1 year ago
Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.950.950, point, 95 pro
bearhunter [10]

The question is incomplete. Here is the complete question:

Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.95 probability that he will hit it. One day, Samir decides to attempt to hit  10 such targets in a row.

Assuming that Samir is equally likely to hit each of the 10 targets, what is the probability that he will miss at least one of them?

Answer:

40.13%

Step-by-step explanation:

Let 'A' be the event of not missing a target in 10 attempts.

Therefore, the complement of event 'A' is \overline A=\textrm{Missing a target at least once}

Now, Samir is equally likely to hit each of the 10 targets. Therefore, probability of hitting each target each time is same and equal to 0.95.

Now, P(A)=0.95^{10}=0.5987

We know that the sum of probability of an event and its complement is 1.

So, P(A)+P(\overline A)=1\\\\P(\overline A)=1-P(A)\\\\P(\overline A)=1-0.5987\\\\P(\overline A)=0.4013=40.13\%

Therefore, the probability of missing a target at least once in 10 attempts is 40.13%.

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