What are the domain and range of function p within the context of Melissa's garden?

The volume of the sphere is StartFraction 500 Over 3 EndFractionπ cubic units. A sphere has a radius of x units. What is the val

Tpy6a [65]

Answer:

(b) Radius of the sphere = 5 units.

Step-by-step explanation:

Here, given:

The volume of the sphere = $(\frac{500}{3})\pi$ cubic units ... (1)

Also, radius of the sphere = x units

Now, VOLUME OF SPHERE = $(\frac{4}{3}) \pi r^3$

So, volume of a sphere with radius x = $(\frac{4}{3}) \pi (x)^3$

But volume of sphere is given by (1).

$\implies (\frac{500}{3})\pi = (\frac{4}{3}) \pi (x)^3\\\implies (\frac{500}{3}) = (\frac{4}{3}) (x)^3\\\implies x^3 = (\frac{500}{3}) \times (\frac{3}{4}) = 125\\\implies x^ 3 = 125 = (5)^3\\\implies x = 5$

Hence, radius of the sphere = 5 units.

4 0

2 years ago

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Seven Applicants for a Job - F, G, H, I, J, K, and L are each to be interviewed on monday or Tuesday . Each

stiks02 [169]

Answer:

I would guess its D. Because it is the one that makes the most sense.

Step-by-step explanation:

H and L has to be on the same day with no other application so not A, B, or C because there is L in all of them.

Hope I helped!

6 0

1 year ago

A drawer contains black socks and white socks. 80% of the socks are white socks. A number generator simulates randomly selecting

Alina [70]

Answer;

The generator was not fair.

Explanation;

The number generator is not fair. This is because the correct percentage of black socks was not chosen at all.

7 0

1 year ago

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The coordinates of the vertices of △PQR are P(1, 4) , Q(2, 2) , and R(−2, 1) . The coordinates of the vertices of △P′Q′R′ are P′

sveticcg [70]

ANSWER

The correct answer is B

<u>EXPLANATION</u>

If we analyse the coordinates carefully, you realize there is a mapping of

$(x,y)\rightarrow(-x,y)$

This is a reflection in the y-axis.

Since the transformation is a reflection, the shape is preserved. Therefore, the image triangle P'Q'R' of triangle

PQR are congruent.

5 0

1 year ago

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Circle Q is centered at the origin with radius r. Point P(x, y) lies on circle Q. Make a conjecture. How can you find an equatio

salantis [7]

Answer:

The relation $x^{2} +y^{2} =r^{2}$ is explained below.

Step-by-step explanation:

P(x, y) is a point on the circle. Q is the origin. Join PQ.

PQ is the radius.

Therefore, PQ = r

Draw PS perpendicular to the x-axis.

Now, ΔPQS is a right triangle.

By Pythagoros theorem,

$PQ^{2}=PS^{2} +QS^{2}$

$r^{2}=x^{2} +y^{2}$

$x^{2} +y^{2} =r^{2}$

5 0

2 years ago

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