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Kazeer [188]
1 year ago
14

Quadrilateral ABCD is translated down and left to form quadrilateral OLMN. If AB = 6 units, BC = 5 units, CD = 8 units, and AD =

10 units, what is LO? 5 units 6 units 8 units 10 units
Mathematics
2 answers:
Temka [501]1 year ago
7 0
1. ABCD is shifted some units down, and then some othe units left.

2. The figure is just moved, not reflected, not diluted. So the distances are preserved

3. ABCD is translated to OLMN mean that AB has been translated to OL, so length of LO=OL=AB= 6 units
nika2105 [10]1 year ago
6 0

Answer:

The correct option is 2. The length of LO is 6 units.

Step-by-step explanation:

Translation is a rigid transformation. It means the image and preimage are congruent.

It is given that quadrilateral ABCD is translated down and left to form quadrilateral OLMN. It means after a rigid transformation OLMN is the image of ABCD. So,

ABCD\cong OLMN

Now, we can say that

AB\cong OL

6\cong OL                              [\becasue AB=6]

6\cong LO                             [\becasue Reflexive property, LO=OL]

Therefore the length of LO is 6 units and the correct option is 2.

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A cell tower is located 3 miles east and 4 miles north of the center of a small town. The cell tower has a coverage radius of 3
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Answer:

The answer is below

Step-by-step explanation:

A cell tower is located 3 miles east and 4 miles north of the center of a small town. The cell tower has a coverage radius of 3 miles.

a) Start by drawing a diagram of this situation. Your diagram might include a coordinate plane, the cell tower, and a circle representing the cell tower's coverage boundary.

a) A house is located 5 miles north of the center of the town and is to the east of the cell tower. If the house lies on the boundary of the cell tower's coverage, how far east of the center of the town is the house?

Answer:

Let the center of the town represent the origin (0,0). Also 1 unit = 1 mile. Since the cell tower is located 3 miles east and 4 miles north of the center of a small town, it is represented by A(3, 4)

The cell tower has a coverage of radius 3 miles. This can be represented by a circle with equation:

(x - a)² + (y - b)² = r². where (a,b) is the center of the circle and r is the radius. Hence:

(x - 3)² + (y - 4)² = 3²

(x - 3)² + (y - 4)² = 9

The diagram is drawn using geogebra.

b) The house is 5 miles north. It can be represented by y = 5 line.

To find the distance east of the house we have to substitute y = 5 and solve for x, hence:

(x - 3)² + (y - 4)² = 9

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(x - 3) = √8

x - 3 = ±2.83

x = 3 ± 2.83

x = 5.83 or 1.83

Since it is to the east to the cell tower, hence x = 5.83.

Therefore the house is located 5.83 miles to the east of the cell tower

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