Quadrilateral ABCD is translated down and left to form quadrilateral OLMN. If AB = 6 units, BC = 5 units, CD = 8 units, and AD =
2 answers:
Answer:
The correct option is 2. The length of LO is 6 units.
Step-by-step explanation:
Translation is a rigid transformation. It means the image and preimage are congruent.
It is given that quadrilateral ABCD is translated down and left to form quadrilateral OLMN. It means after a rigid transformation OLMN is the image of ABCD. So,
Now, we can say that
Therefore the length of LO is 6 units and the correct option is 2.
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Answer:
There is no significant difference between the two averages at 5% level
Step-by-step explanation:
Given that a a college student is interested in testing whether business majors or liberal arts majors are better at trivia.
The student gives a trivia quiz to a random sample of 30 business school majors and finds the sample’s average test score is 86. He gives the same quiz to 30 randomly selected liberal arts majors and finds the sample’s average quiz score is 89
Thus he has done a hypothesis testing for comparison of two means of different subjects. n =30
Since which is better is not claimed we use two tailed test here
We find that p value our alpha
Since p >alpha, we find that there is no significant difference between the averages of these two groups and null hypothesis is accepted
Answer:
For this case the 95% confidence interval is given (63.5 , 74.4) and we want to conclude about the result. For this case we can say that the true mean of heights for male students would be between 63.5 and 74.4. And the best answer would be:
b. The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches.
Step-by-step explanation:
Notation
represent the sample mean for the sample
population mean (variable of interest)
s represent the sample standard deviation
n represent the sample size
Solution to the problem
The confidence interval for the mean is given by the following formula:
(1)
In order to calculate the mean and the sample deviation we can use the following formulas:
(2)
(3)
In order to calculate the critical value we need to find first the degrees of freedom, given by:
For this case the 95% confidence interval is given (63.5 , 74.4) and we want to conclude about the result. For this case we can say that the true mean of heights for male students would be between 63.5 and 74.4. And the best answer would be:
b. The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches.