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Kazeer [188]
1 year ago
14

Quadrilateral ABCD is translated down and left to form quadrilateral OLMN. If AB = 6 units, BC = 5 units, CD = 8 units, and AD =

10 units, what is LO? 5 units 6 units 8 units 10 units
Mathematics
2 answers:
Temka [501]1 year ago
7 0
1. ABCD is shifted some units down, and then some othe units left.

2. The figure is just moved, not reflected, not diluted. So the distances are preserved

3. ABCD is translated to OLMN mean that AB has been translated to OL, so length of LO=OL=AB= 6 units
nika2105 [10]1 year ago
6 0

Answer:

The correct option is 2. The length of LO is 6 units.

Step-by-step explanation:

Translation is a rigid transformation. It means the image and preimage are congruent.

It is given that quadrilateral ABCD is translated down and left to form quadrilateral OLMN. It means after a rigid transformation OLMN is the image of ABCD. So,

ABCD\cong OLMN

Now, we can say that

AB\cong OL

6\cong OL                              [\becasue AB=6]

6\cong LO                             [\becasue Reflexive property, LO=OL]

Therefore the length of LO is 6 units and the correct option is 2.

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According to a Los Angeles Times study of more than 1 million medical dispatches from 2007 to 2012, the 911 response time for me
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Answer:

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c)IQR = Q_3 -Q_1 = 11.05-10.55=0.5

And we can find the usual limits with:

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Upperer = Q_3 +1.5 IQR = 10.55 +1.5*0.5=11.3

And since 8.3 <9.8 we can consider this value too low or as an outlier for this case.

d) The mean for this case was 10.65 and the usual values are between 9.8 and 11.3, so as we can see all are above the specified value of 6 minutes, and we can conclude that the times are not satisfying the quality standards for this case.

And they should be considered apply some strategies to reduce the response time, adding more stations around points selected at the city could be useful in order to reduce the response time.

Step-by-step explanation:

We have the following data:

11.8 10.3 10.7 10.6 11.5 8.3 10.5 10.9 10.7 11.2

Part a

We can calculate the sample mean with the following formula:

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And if we replace we got: \bar X=10.65

For the median we need to sort the values on increasing order and we have:

8.3 10.3 10.5 10.6 10.7 10.7 10.9 11.2 11.5 11.8

Since n =10 we can calculate the median as the average between the 5th and 6th position of the dataset ordered and we got:

Median =\frac{10.7+10.7}{2}=10.7

The mode would be the most repeated value on this case:

Mode= 10.7

Part b

The range is defined as Range =Max-Min and if we replace we got:

Range = 11.8-8.3=3.5

We can calculate the standard deviation with the following formula:

s= sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And if we replace we got:

s= 0.948

Part c

For this case we can use the IQR method in order to determine if 8.3 is an outlier or not.

We can calculate the first quartile with these values: 8.3 10.3 10.5 10.6 10.7 10.7 and Q_1= \frac{10.6+10.7}{2}=10.55

And for the Q3 we can use: 10.7 10.7 10.9 11.2 11.5 11.8 and we got Q_3 = \frac{10.9+11.2}{2}=11.05

Then we can find the IQR like this:

IQR = Q_3 -Q_1 = 11.05-10.55=0.5

And we can find the usual limits with:

Lower = Q_1 -1.5 IQR = 10.55 -1.5*0.5=9.8

Upperer = Q_3 +1.5 IQR = 10.55 +1.5*0.5=11.3

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Part d

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