5c+3b=29.99
3c+7b=32.71
15c+9b=89.97
15c+35b=163.55
26b=73.58
b=2.83
c=4.30
A) In order to create a sampling plan, you need to follow the following 5 steps:
1) Define the sample population: who are the customers you want to contact?
The costumers who bought a new car on a certain year.
2) Define the size of population: how many customers are you going to contact?
Of the 30000 customers who bought a car, you want to contact 1000 customers.
3) Define the contact options: how are you going to contact the customers?
You have a list of names and addresses, therefore you can send a questionnaire via mail.
4) Form a sampling frame: what is the time or contact frame to get in touch with your customers?
You will send the questionnaires and you will wait two months for the answer.
5) Define the analysis method: is yours a qualitative or quantitative research?
In your case, you want a quantitative research and therefore a probabilistic sampling.
B) The 32.5% probability refers to customers having issues with the power doors locks among the costumers who had problems, it does not consider the customers who did not have any problem or those who had problems after the first 5000 miles.
C) In order to find the probability of a power door lock problem if there have been problems within the first 5000 miles, we need to consider the whole sample:
P = 13 / 1000
= 0.013
Therefore,
N = <span>0.013 </span>× 30000
= 390
Hence, the number of new cars sold that experienced a problem with the power door locks within the first 5000 miles will be 390.
Answer:
a) 0.88
b) 0.35
c) 0.0144
d) 0.2084
e) 0.7916
Step-by-step explanation:
a) The probability of a peanut being brown is 12/100 = 0.12. Hence the probability of it not being brown is 1-0.12 = 0.88
b) 12% of peanuts are brown, 23% are blue. So 35% are either blue or brown. The probability of a peanut being blue or brown is, therefore 35/100 = 0.35.
c) 12% of peanuts are red, so the probability of a peanut being red is 12/100 = 0.12. In order to calculate the probability of 2 peanuts being both red, we can assume that the proportion doesnt change dramatically after removing one peanut (because the number of peanuts is absurdly high. We can assume that we are replenishing the peanuts). To calculate the probability of 2 peanuts being both red, we need to power 0.12 by 2, hence the probability is 0.12² = 0.0144.
d) Again, we will assume that the probability doesnt change, because we replenish. The probability of a peanut being blue is 0.23. The probability of it not being blue is 0.77, so the probability of 6 peanuts not being blue is obtained from powering 0.77 by 6, hence it is 0.77⁶ = 0.2084
e) The event 'at least one peanut is blue' is te complementary event of 'none peanuts are blue', so the probability of this event is 1- 0.2084 = 0.7916
Answer:
Children = 51
Adults = 42
Students= 84
Step-by-step explanation:
Children = $2
Students = $3
Adults = $4
Total sales = $522
Total people who attended = 177
Adults =a
Students = s= 2a
Children = c
c+s+a = 177 (1)
2c+3s+4a=522 (2)
Substitute s=2a into the equations
c + 2a + a = 177
c + 3a = 177 (3)
2c + 3(2a) + 4a = 522
2c + 6a + 4a = 522
2c + 10a = 522 (4)
c + 3a = 177 (3)
2c + 10a = 522 (4)
Multiply (3) by 2
2c + 6a = 354 (3b)
2c + 10a = 522
Subtract (3b) from (4)
10a - 6a = 522 - 354
4a = 168
Divide both sides by 4
a= 168/4
= 42
a= 42
s= 2a
= 2(42)
= 84
s= 84
Substitute the value of s and a into (1)
c+s+a = 177 (1)
c + 84 + 42 = 177
c + 126 = 177
c = 177 - 126
= 51
c=51
Children = 51
Adults = 42
Students= 84
