Answer:
Compatible width of rectangular banquet hall could be 90 feet approximately.
Step-by-step explanation:
Given
Area of a rectangular banquet hall = 7400 square feet
Length of rectangular banquet hall = 82 feet
We need to calculate width of the rectangular banquet hall.
Now Area of rectangle is equal to length times width.
Framing in equation form we get;
Substituting the given values we get;
Now by definition of Compatible numbers which state that:
"Compatible numbers are the numbers that are easy to add, subtract, multiply, or divide mentally. Compatible numbers are close in value to the actual numbers that make estimating the answer and computing problems easier."
Now By Using width as 90 feet and length as 82 feet we get area as 7380 sq ft. which is closet to actual area which is 7400 sq ft.
Hence we can say compatible width could be 90 feet approximately.
What is the potential outlier in the following data set of populaion densities? 1,19,35,43,49,55,63,94,105,110,175,231,239,351,7
MAXImum [283]
Answer:
738
Step-by-step explanation:
It’s to different from the other numbers
On average, parents pay 10% of the total amount due with borrowed funds; students cover 14% with student loans and other debt-forming sources. The remaining 29% of the cost of college is mostly covered by scholarships and grants won by the student: 17% by scholarships and 11% by grants.
Answer:
Top-to-bottom, the boxes have this order in the proof: 1, 7, 4, 3, 9, 8, 5, 2, 6.
Step-by-step explanation:
The basic idea is to use the Pythagorean theorem to write two expressions for the length of altitude BD, also called "k", then equate them and simplify the result. This leaves an expression for DC, also called "x", which is replaced by a cosine expression to complete the proof.
Finally, the variations involving other combinations of sides and angles are suggested as being provable in the same way.
Answer:
Heidi hass really kong hair and should cut it
