<h3><u>The equation of the circle that has its center at (-27, 120) and passes through the origin is</u>:</h3>

<em><u>Solution:</u></em>
<em><u>The equation of a circle is given as:</u></em>

Where,
(a, b) is the centre of the circle
r is the radius
We have the centre of the circle (-27, 120)
Therefore,
a = -27
b = 120
Given that, it passes through origin. which means, (x, y) = (0, 0)
Substitute (a, b) = (-27, 120) and (x, y) = (0, 0) in eqn

Substitute
= 15129 and (a, b) = (-27, 120) in eqn

Thus the equation of circle is found