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2 years ago

Which angle In ABC has the largest measure ?

Mathematics

2 answers:

antiseptic1488 [7]2 years ago

8 0

Answer:

Option B. ∠B

Step-by-step explanation:

In this question three sides of a triangle are given as AB = 10, BC = 10, AC = 12

and we have to tell the largest angle of the triangle.

As per sine rule we know

sin A/BC = sin B/ AC = sin C/ AB

Here sin A/10 = sin C/10

⇒sin A = sin C

therefore ∠A = ∠C

(sin B)/12 = (sin C)/10

⇒ sin B/ sin C = 12/10 = 1.2 : 1

Therefore ∠B:∠C :: 1.2 : 1

similarly ∠B:∠A :: 1.2 : 1

Therefore ∠B is the largest angle.

Rus_ich [418]2 years ago

4 0

The angle with the largest measure is opposite the longest side. The longest side is 12. It is opposite angle B. The appropriate choice is ...

B. ∠B

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1 year ago

What is the probability that a point chosen at random in the rectangle is also in the blue triangle? A triangle inside of a rect

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2 years ago

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A textbook store sold a combined total 402 of psychology and math textbooks in a week. The number of psychology textbooks sold w

uranmaximum [27]

Answer:

The number of textbooks of each type were sold is <u>134 math </u>and <u>268 psychology </u>books.

Step-by-step explanation:

Given:

Total number of math and psychology textbooks sold in a week is 402.

Now, let the number of math textbooks sold be $x$ .

And, the number of psychology textbooks be $2x$ .

According to question:

$x+2x=402$

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Dividing both sides by 3 we get:

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2 years ago

Which statements about the local maximums and minimums for the given function are true? Choose three options.

Nostrana [21]

Answer:

Over the interval [2, 4], the local minimum is –8.

Over the interval [3, 5], the local minimum is –8.

Over the interval [1, 4], the local maximum is 0.

Step-by-step explanation:

The true statements are:

Over the interval [2, 4], the local minimum is –8.

Over the interval [3, 5], the local minimum is –8.

Over the interval [1, 4], the local maximum is 0.

Lets discuss each option one by one:

Over the interval [1, 3], the local minimum is 0

This is a false statement. Look at the graph. The minimum point given is (3.4,-8). Therefore the local minimum is -8 not 0

Over the interval [2, 4], the local minimum is –8.

This statement is true because the given minimum point is(3.4, -8). Thus the local minimum is -8 which is true

Over the interval [3, 5], the local minimum is –8.

According to the given minimum point, the local minimum is -8 which is true

Over the interval [1, 4], the local maximum is 0.

Look at the graph. The maximum point given is (2,0). Thus this statement is true because local maximum is 0.

Over the interval [3, 5], the local maximum is 0.

This is a false statement because there is no maximum point

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2 years ago

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SVETLANKA909090 [29]

Answer:

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Step-by-step explanation:

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2 years ago