All categories

2 years ago

Which angle In ABC has the largest measure ?

Mathematics

2 answers:

antiseptic1488 [7]2 years ago

8 0

Answer:

Option B. ∠B

Step-by-step explanation:

In this question three sides of a triangle are given as AB = 10, BC = 10, AC = 12

and we have to tell the largest angle of the triangle.

As per sine rule we know

sin A/BC = sin B/ AC = sin C/ AB

Here sin A/10 = sin C/10

⇒sin A = sin C

therefore ∠A = ∠C

(sin B)/12 = (sin C)/10

⇒ sin B/ sin C = 12/10 = 1.2 : 1

Therefore ∠B:∠C :: 1.2 : 1

similarly ∠B:∠A :: 1.2 : 1

Therefore ∠B is the largest angle.

Rus_ich [418]2 years ago

4 0

The angle with the largest measure is opposite the longest side. The longest side is 12. It is opposite angle B. The appropriate choice is ...

B. ∠B

You might be interested in

Find the values of x1 and x2 where the following two constraints intersect.

Arte-miy333 [17]

Answer: x1 = 251/26, x2 = -111/26

Step-by-step explanation:

Hi!

As you can see in the figure, the point you are looking for is the intersection of two lines.

The intersection point is found solving this system of linear equations (the point must satisfy both equations):

$9x_1 +7x_2=57\\4x_1 + 6x_2 = 13$

You can solve it, for example, by the method of substitution:

$\text{solve for x1 in the first equation:}\\x_1 = \frac{1}{9}(57 - 7x_2)$

Then plug x1 into equation 2, and solve for x2:

$\frac{4}{9}(57-7x_2) + 6x_2 = 13\\\text{doing the algebra you get:}\\x_2 = \frac{-111}{26}$

Then you use the value of x2 to get x1:

$x_1 = \frac{1}{9}(57 - 7x_2)= \frac{1}{9}(57 + 7*\frac{111}{26}) = 251/26\\$

4 0

2 years ago

A moving company charges $0.60 per pound for a move from New York to Florida. A family estimates that their belongings weigh abo

HACTEHA [7]

The answer would be - 4,800

3 0

2 years ago

Select the correct answer.

Maslowich

Answer:

x is the correct answer

4 0

2 years ago

The angle measures associated with which set of ordered pairs share the same reference angle

Trava [24]

Answer:

Option 3 is right.

Step-by-step explanation:

Reference angle of x is obtained by either 180-x, 180+x. or 360-x depending on the posiiton of terminal whether II quadrant or iv quadrant, or iii quadrant, etc.

In whatever way we find reference angles,

cos will remain cos only and sin will remain sin only there may be only changes in sign.

Of all the ordered pairs given, we find that I, II, and Iv there is a switch over form cos to sine and sin to cos. Hence these options cannot be for reference angles.

III option is $(-\frac{1}{2} ,\frac{-\sqrt{3} }{2} )(\frac{1}{2} ,\frac{\sqrt{3} }{2} )$

show that both sign and cos changed sign. This is possible only in III quadrant.

ie reference angle of orignal angle t = 180+t

SO this option is right.

7 0

2 years ago

Read 2 more answers

If a(x) = 3x + 1 and b (x) = StartRoot x minus 4 EndRoot, what is the domain of (b circle a) (x)?

kiruha [24]

Answer:

$[1,\infty)$

Step-by-step explanation:

$b(x)=\sqrt{x-4}$

$a(x)=3x+1$

Since we want to know the domain of $(b \circ a)(x)$ , let's first consider the domain of the inside function, that is, that of $a(x)=3x+1$ . Every polynomial function has domain all real numbers.

So we can plug anything for function $a$ and get a number back.

Now the other function is going to be worrisome because it has a square root. You cannot take square root of negative numbers if you are only considering real numbers which that is the case with most texts.

Let's find $(b \circ a)(x)$ and simplify now.

$(b \circ a)(x)$

$b(a(x))$