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svp [43]
2 years ago
15

while driving with his father, Amit his guys breath whenever they pass through a particular tunnel. Amit counts the number of se

conds he holds his breath, from the beginning of the tunnel to the end of the tunnel, and finds he good his breath, on average, for about 8 seconds. if his father drives the car at 60 miles per hour through the tunnel, according to the average time Amit his his breath, about how long is the tunnel? (there are 5280 feet in a mile)
Mathematics
2 answers:
vova2212 [387]2 years ago
8 0
The answer is 700 feet, because if you divide 5,280 feet by 1 mile you get 88 feet per second, then you multiply 88 feet by 8 seconds you get 704 feet. Since the question said "about" I am assuming that means rounding. You round 704 to 700 and that's how you get the answer.  
Lelechka [254]2 years ago
7 0

Answer: 704 feet

Step-by-step explanation: speed of car is V= 60 miles per hour

First convert the speed from miles per hour to feet per second .

V=\frac{60\times 5280}{60\times 60} \frac{ft}{s} = 88 \frac{ft}{s}

Now Length of tunnel , L= speed of car x time taken

Therefore L=88\times 8 feet=704 feet

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Dafna11 [192]

Answer:

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Step-by-step explanation:

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2 years ago
Option A to buy has a total cost of 20,579 dollars, up-front cost of 2,500 dollars, monthly payment of 338 dollars for 60 months
Vladimir [108]

Answer:

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Step-by-step explanation:

it B pls mark me i calculated it 4 time pls

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2 years ago
Describe the graph represented by the equation r=5/(3+2 sin theta).
Yuki888 [10]
We have the following equation:

r= \frac{5}{3+2sin(\theta)}

If we graph this equation we realize that in fact this is an ellipse with major axis matching the y-axis. So we can recognize these characteristics:

1. Center of the ellipse: 

The midpoint C<span> of the line segment joining the foci is called the </span>center<span> of the ellipse. So in this exercise this point is as follows:
</span>
C(0, -2)

2. Length of major axis:

The line through the foci is called the major axis<span>, so in the figure if you go from -5, at the y-coordinate, and walk through this major axis to the coordinate 1, the distance you run is the length of the major axis, that is:</span>

6 \ units

3. Length of minor axis:

The line perpendicular to the foci through the center is called the minor axis. So in the figure if you go from -2, at the x-coordinate, and walk through this minor axis to the coordinate 2, the distance you run is the length of the minor axis, that is:

4 \ units

4. Foci:

Let's find c as follows:

c=\sqrt{a^{2}-b^{2}}=\sqrt{3^{2}-2^{2}}=\sqrt{5}

Then the foci are:

f_{1}=(0, \sqrt{5}-2)

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8 0
1 year ago
F⃗ (x,y)=−yi⃗ +xj⃗ f→(x,y)=−yi→+xj→ and cc is the line segment from point p=(5,0)p=(5,0) to q=(0,2)q=(0,2). (a) find a vector pa
DerKrebs [107]

a. Parameterize C by

\vec r(t)=(1-t)(5\,\vec\imath)+t(2\,\vec\jmath)=(5-5t)\,\vec\imath+2t\,\vec\jmath

with 0\le t\le1.

b/c. The line integral of \vec F(x,y)=-y\,\vec\imath+x\,\vec\jmath over C is

\displaystyle\int_C\vec F(x,y)\cdot\mathrm d\vec r=\int_0^1\vec F(x(t),y(t))\cdot\frac{\mathrm d\vec r(t)}{\mathrm dt}\,\mathrm dt

=\displaystyle\int_0^1(-2t\,\vec\imath+(5-5t)\,\vec\jmath)\cdot(-5\,\vec\imath+2\,\vec\jmath)\,\mathrm dt

=\displaystyle\int_0^1(10t+(10-10t))\,\mathrm dt

=\displaystyle10\int_0^1\mathrm dt=\boxed{10}

d. Notice that we can write the line integral as

\displaystyle\int_C\vecF\cdot\mathrm d\vec r=\int_C(-y\,\mathrm dx+x\,\mathrm dy)

By Green's theorem, the line integral is equivalent to

\displaystyle\iint_D\left(\frac{\partial x}{\partial x}-\frac{\partial(-y)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=2\iint_D\mathrm dx\,\mathrm dy

where D is the triangle bounded by C, and this integral is simply twice the area of D. D is a right triangle with legs 2 and 5, so its area is 5 and the integral's value is 10.

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jeka57 [31]

Answer:

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Step-by-step explanation:

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