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sashaice [31]
2 years ago
8

Describe the graph represented by the equation r=5/(3+2 sin theta).

Mathematics
1 answer:
Yuki888 [10]2 years ago
8 0
We have the following equation:

r= \frac{5}{3+2sin(\theta)}

If we graph this equation we realize that in fact this is an ellipse with major axis matching the y-axis. So we can recognize these characteristics:

1. Center of the ellipse: 

The midpoint C<span> of the line segment joining the foci is called the </span>center<span> of the ellipse. So in this exercise this point is as follows:
</span>
C(0, -2)

2. Length of major axis:

The line through the foci is called the major axis<span>, so in the figure if you go from -5, at the y-coordinate, and walk through this major axis to the coordinate 1, the distance you run is the length of the major axis, that is:</span>

6 \ units

3. Length of minor axis:

The line perpendicular to the foci through the center is called the minor axis. So in the figure if you go from -2, at the x-coordinate, and walk through this minor axis to the coordinate 2, the distance you run is the length of the minor axis, that is:

4 \ units

4. Foci:

Let's find c as follows:

c=\sqrt{a^{2}-b^{2}}=\sqrt{3^{2}-2^{2}}=\sqrt{5}

Then the foci are:

f_{1}=(0, \sqrt{5}-2)

f_{2}=(0, -\sqrt{5}-2)

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the anwser is in the text

Step-by-step explanation:

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a five foot boy casts a 2 foot shadow. At the same time the shadow of the court house tower is 25 feet in length. How tall is th
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Answer:

The court house tower should be 51 feet tall.

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2.5+2.5=5 feet because 2+2=4 and 0.5+0.5=1. 4+1=5

25.5+25.5=51 because 25+25=50 and 0.5+0.5=1. 50+1=51

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What are the coordinates of the circumcenter of this triangle? Enter your answer in the boxes.
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Answer:

(2,1)

Step-by-step explanation:

We can see  that the given triangle.

The coordinates of A are (-1,5) .

The coordinates of B are (-1,-3).

The coordinates of C are  (5,-3).

Distance formula: \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

AB=\sqrt{(-3-5)^2+(-1+1)^2}=8 units

BC=\sqrt{(5+1)^2+(-3+3)^2}=6 units

AC=\sqrt{(5+1)^2+(-3-5)^2}=10 units

Pythagoras theorem:(Hypotenuse)^2=(Base)^2+(Perpendicular\;side)^2}

AB^2+BC^2=8^2+6^2=100

AC^2=(10)^2=100

Therefore, AC^2=AB^2+BC^2

When a triangle satisfied the Pythagoras theorem then, the triangle is right triangle.

Hence, the given triangle is  a right triangle.

We know that circum-center of right triangle is the mid point of hypotenuse.

Mid-point formula:x=\frac{x_1+x_2}{2},y=\frac{y_1+y_2}{2}

Using this formula then, we get

Mid-point of hypotenuse AC is given by

x=\frac{-1+5}{2}=2,y=\frac{5-3}{2}=1

Hence, the circum-center of triangle is (2,1).

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If a diameter of a circle with a circumference of 104.48 mm is reduced by 1/2,what is the circumference of the new circle?
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All we need to do here is divide the circumference by 2.

104.48 / 2 = 52.24

The new circumference is 52.24 mm.
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