To solve that we first need to write it as an equation where x is the number:
85 + x^2 = (x-17)^2
85 + x^2 = x^2 - 34x + 289
Now organize the equation by gathering like terms in the same side lf the equation:
You can shift 85 to the other side by subtracting 85 from both sides of the equation:
85 - 85 + x^2 =x^2 34x +289 - 85
x^2 =x^2 + 34x +204
And shift x^2 to the other side by subtracting x^2 from both sides:
x^2 - x^2 =x^2 -x^2 + 34x +204
0 = 34x + 204
Shift 34x to the other side by subtracting 34x from sides
-34x = 34x - 34x + 204
-34x = 204
And now isolate x by dividing both sides of the equation by -34
-34/-34x = 204/-34
x = -6
Thats your awnser , the number is -6
I hope you understood my brief explanation...
Answer:option B & D are correct
Step-by-step explanation:
Given options are
A B C D E
Tether ball pole shadow 1.35 1.8 3.75 0.6 2
Flagpole shadow 3.4 4.08 8.35 1.36 4.8
Ratio of corresponding height & shadows should be same
3 meter tall tether ball pole and a 6.8 tall flagpole
=> Ratio = 6.8/3 = 68/30 = 34/15
A - 3.4/1.35 = 340/135 ≠ 34/15( 306/135)
B - 4.08/1.8 = 408/180 = 34/15 = 34/15 ( Correct option)
C 8.35/3.75 = 835/375 = 167/75 ≠ 34/15( 170/75)
D 1.36/0.6 = 136/60 = 34/15 = 34/15 ( Correct option)
E 4.8/2 = 48/20 = 12/5 = 36/15 ≠ 34/15
option B & D are correct
(a) Data with the eight day's measurement.
Raw data: [60,58,64,64,68,50,57,82],
Sorted data: [50,57,58,60,64,64,68,82]
Sample size = 8 (even)
mean = 62.875
median = (60+64)/2 = 62
1st quartile = (57+58)/2 = 57.5
3rd quartile = (64+68)/2 = 66
IQR = 66 - 57.5 = 8.5
(b) Data without the eight day's measurement.
Raw data: [60,58,64,64,68,50,57]
Sorted data: [50,57,58,60,64,64,68]
Sample size = 7 (odd)
mean = 60.143
median = 60
1st quartile = 57
3rd quartile = 64
IQR = 64 -57 = 7
Answers:
1. The average is the same with or without the 8th day's data. FALSE
2. The median is the same with or without the 8th day's data. FALSE
3. The IQR decreases when the 8th day is included. FALSE
4. The IQR increases when the 8th day is included. TRUE
5. The median is higher when the 8th day is included. TRUE
Let the distance be d
Using pythagorean theorem,
d ≈ 119
The player ran for
119 meters
Answer:
1.5s+2.5p<20
Step-by-step explanation:
Multiply by each kilo and then make sure it adds up to less than 20!
