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spayn [35]
2 years ago
15

Which normal distribution has a wider​ spread: the one with mean 9 and standard deviation 5 or the one with mean 5 and standard

deviation 9​?
Mathematics
1 answer:
Fofino [41]2 years ago
7 0

The spread is controlled by the standard deviation. The mean value only controls where the center of the bell is.


So a normal distribution with a sigma of 9 is wider than one with a sigma of 5.



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Automated electron backscattered diffraction is now being used in the study of fracture phenomena. The following information is
lilavasa [31]

Answer:

a) Proportion of the sampled angles are at least 30° = 0.144

b) Proportion of sampled angles between 10 and 25 = 0.415

Step-by-step explanation:

Class Relative Frequency

0-<5                 0.176

5-<10                0.169

10-<15          0.179

15-<20          0.139

20-<30          0.193

30-<40          0.075

40-<60          0.04

60-<90          0.029

A) Proportion of the sampled angles which are at least 30° can be calculated by adding the relative frequencies which are greater than 30. This will include the classes 30-<40, 40-<60 and 60-<90, So,

proportion of the sampled angles are at least 30° = 0.075 + 0.04 + 0.029

proportion of the sampled angles are at least 30° = 0.144

B) For the proportion of angles between 10 and 25, we need to consider the classes 10-<15, 15-<20 and 20-<30. Since we are interested in the angles up till 25 degrees, we need to divide the relative frequency of the class 20-<30 by 2 because 25 lies in the middle of this class. So,

Proportion of sampled angles between 10 and 25 = 0.179 + 0.139 + (0.193/2)

Proportion of sampled angles between 10 and 25 = 0.415

C) For constructing the histogram, you need to plot the relative frequencies on the y axis and the classes on the x-axis by choosing a suitable scale for both the axes. I have plotted the graph on paint but its a bit untidy. I am attaching the graph as a snippet here so that you can have an idea of the heights.  

By looking at the heights of the classes, we can say that <u>The distribution of misorientation angles is heavily positively skewed</u> because there is a tail at the positive side of the graph. The graph is also unimodal since there is only one highest peak present.

7 0
2 years ago
It is 4 : 12 p.M. 4:12 p.M.4, colon, 12, start text, space, p, point, m, point, end text Emma's mom will be home from work in 70
Vaselesa [24]

Answer:

40 Minutes.

Step-by-step explanation:

The current time = 4:12 p.M.

Emma's mom will be home from work in 70 minutes.

70 minutes = 1 hour 10 Minutes= 1: 10 Hours

\left\begin{array}{ccccc}&4&:&12 &p.m.\\+&1&:&10&\\--&--&--&--&--\\&5&:&22&p.m\end{array}\right

Therefore, Emma's Mom will get home by 5: 22 p.m.

Emma has gymnastics lessons at 6 : 00 p.M.

To determine how much time Emma will have between the time that her mom gets home from work and the beginning of gymnastics lessons, we simply subtract 5:22 from 6.

\left\begin{array}{ccccc}&6&:&00 &p.m.\\-&5&:&22&\\--&--&--&--&--\\&00&:&40&\end{array}\right

Emma  will have 40 Minutes.

5 0
2 years ago
Dukes science quiz scores are 99,91,60,94,and 95 . Describe the effect of the outlier on the mean and median
lilavasa [31]
I don't know the effect, but I can tell you the outlier, mean, and the median.
Outlier: 60
Mean: 87.8
Median: 60
3 0
2 years ago
Read 2 more answers
Operations: Housekeeping Math Quiz
masha68 [24]

Answer:

Total time = 63 hours

Step-by-step explanation:

First, let us write out the information in the question:

rate at which rooms are cleaned = 20 mins/room

number of rooms = 175

one-fifth of the rooms take 40% longer to clean

Next, let us convert the extra time taken to clean the rooms from percentage to time.

40% of normal cleaning time = 40% of 20

= 40/100 × 20 = 0.4 × 20 = 8 minutes

∴ onw-fifth of the rooms take an extra 8 minutes = 28 minutes in total

Next, let us calculate how many of those rooms in the total 175 takes the extra cleaning time:

one-fifth of the rooms takes 28 minutes to clean means that:

1 in every 5 rooms out of the 175 rooms take 28 minutes to clean

∴ Number of rooms with extra cleaning time = 1/5 of 175

= 1/5 × 175 = 0.2 × 175 = 35

∴ 35 rooms take 28 minutes each to be cleaned.

Now let us calculate the total cleaning time:

if 35 rooms take the extra cleaning time, then the number of rooms that have the normal cleaning time is as follows:

175 - 35 = 140

Total time:

140 rooms taking 20 minutes per room = 140 × 20 = 2,800 munites

35 rooms taking 28 minutes per room = 35 × 28 = 980 minutes

Total cleaning time = 2800 + 980 = 3780 minutes

converting to hours (1 hour = 60 minutes)

∴ 3780 minutes = 3780 ÷ 60 = 63 hours (2 days and 15 hours)

8 0
1 year ago
A group of five people are all working on the same mathematics problem. On the night before it is due, they call each other to d
UkoKoshka [18]

Answer:

Minimum number of calls = 10

Step-by-step explanation:

Lets name the five people as A,B,C,D and E.

<u>On the night before ,each person talks to every other person atleast once that means A would talk to B,C,D and E atleast once.</u>

Lets start with A. He would talk to other 4 people which means there would be 4 phone calls made.

Now lets take B. He can talk to A,C,D and E. But  A has already talked to C therefore to get minimum number of phone calls , B need not call A again. So he calls only C,D and E.

In case of C using similar logic he need to talk to only D and E.

For D , he talks to E alone.

E does not have to talk to anyone as he has already talked to everyone atleast once.

Total calls = 4 + 3 + 2 + 1

                    = 10

5 0
2 years ago
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