Answer: If I am correct the value of x might be f=0
Step-by-step explanation:
Using function concepts, it is found that it is increasing on the interval:
(–∞, –5] ∪ [3, ∞)
---------------
The function is given by:
The graph is given at the end of this question.
- If the function is pointing upwards, it is increasing. Otherwise, it is decreasing.
- In the graph, it can be seen that it is pointing upwards for x of -5 and less, or 3 and higher, thus, the interval is:
(–∞, –5] ∪ [3, ∞)
A similar problem is given at brainly.com/question/13539822
Answer:
Angle OAB = 90°
Reason: tangent theorem of a circle
Step-by-step explanation:
The diagram given shows a tangent line of the given circle with center O. The tangent touches the circle at point A.
The diagram also shows the radius of the circle, OA, drawn from the center to the circle to meet at the point of tangency.
Thus, according to the Tangent Theorem of a circle, the point at which the radius drawn from the center meets the point of tangency = 90°. The tangent is perdendicular to the radius drawn to meet at the point of tangency.
Therefore, angle OAB = 90°
The answer should be Two and Three ...
Answer:
The null hypothesis is that all the different teaching methods have the same average test scores.
H0: μ1 = μ2 = μ3 = μ4 = μ5
The alternative hypothesis is that at least one of the teaching methods have a different mean.
Ha: at least one mean is different. (μ1 ≠ μi)
Step-by-step explanation:
The null hypothesis (H0) tries to show that no significant variation exists between variables or that a single variable is no different than its mean. While an alternative Hypothesis (Ha) attempt to prove that a new theory is true rather than the old one. That a variable is significantly different from the mean.
For the case above, let μ represent the average test scores for the teaching methods:
The null hypothesis is that all the different teaching methods have the same average test scores.
H0: μ1 = μ2 = μ3 = μ4 = μ5
The alternative hypothesis is that at least one of the teaching methods have a different mean.
Ha: at least one mean is different. (μ1 ≠ μi)
