1. First, you must apply the formula
for calculate the sum of the interior angles of a regular polygon, which is
shown below:
(n-2) × 180°
"n" is the number of sides of the polygon (n=5).
2. Then, the sum of the interior angles of the pentagon, is:
(5-2)x180°=540°
3. The problem says that the measure of each of the other interior angles is equal to the sum of the measures of the two acute angles and now you know that the sum of all the angles is 540°, then, you have:
α+α+2α+2α+2α=540°
8α=540°
α=540°/8
α=67.5°
4. Finally, the larger angle is:
2α=2(67.5°)=135°
5. Therefore, the answer is: 135°
Answer:
If the limit that you want to find is 
then you can use the following proof.
Step-by-step explanation:
Let 
and 
be the given polinomials. Then
Observe that
and
Then
Answer:
160m/s
Step-by-step explanation:
The object can hit the ground when t = a; meaning that s(a) = s(t) = 0
So, 0 = -16a² + 400
16a² = 400
a² = 25
a = √25
a = 5 (positive 5 only because that's the only physical solution)
The instantaneous velocity is
v(a) = lim(t->a) [s(t) - s(a)]/[t-a)
Where s(t) = -16t² + 400
and s(a) = -16a² + 400
v(a) = Lim(t->a) [-16t² + 400 + 16a² - 400]/(t-a)
v(a) = Lim(t->a) (-16t² + 16a²)/(t-a)
v(a) = lim (t->a) -16(t² - a²)(t-a)
v(a) = -16lim t->a (t²-a²)(t-a)
v(a) = -16lim t->a (t-a)(t+a)/(t-a)
v(a) = -16lim t->a (t+a)
But a = t
So, we have
v(a) = -16lim t->a 2a
v(a) = -32lim t->a (a)
v(a) = -32 * 5
v(a) = -160
Velocity = 160m/s
i think it would be D i hope i helped
Answer:
What is the longest side?
square root of 1700
What is the square of the longest side?
1700
What is the sum of the squares of the two shorter sides?
1700
Does the window frame form right triangles?
Yes, the sum of the square of the two shorter sides equals the square of the longest side.
