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2 years ago

15

Amina used the quadratic formula to solve an equation. Her result shows two solutions that are complex numbers with imaginary pa

rts. Which expression could be Amina's result?

1 answer:

Mama L [17]2 years ago

6 0

A quadratic equation has either two different real roots, one real root, or two conjugate complex roots (this is the case when the discriminant is negative, i.e. when you have no real roots).

Two conjugate complex roots have the same real part and opposite imaginary parts. So, the solutions to Amina's equation will be in this form:

$a+bi,\ \ a-bi$

For some $a,b\in\mathbb{R},\ b\neq 0$

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Let X, the number of flaws on the surface of a randomly selected boiler of a certain type, have a Poisson distribution with para

kvasek [131]

Answer:

(a) 0.932

(b) 0.0653

(c) 0.032

(d) 0.316

(e) 0.251

Step-by-step explanation:

From the table with mean parameter μ = 5, we can compute the following cumulative and density probability

(a) $P(X \leq 8) = 0.932$ (cumulative)

(b) P(X = 8) = 0.0653 (density)

(c) $P(9 \leq X) = 1 - P(X \leq 9) = 1 - 0.968 = 0.032$ (cumulative)

(d) $P(5 \leq X \leq 8) = P(X \leq 8) - P(X \leq 5) = 0.932 - 0.616 = 0.316$ (cumulative)

(e) $P(5 < X < 8) = P(X \leq 8) - P(X \leq 5) - P(X = 8) = 0.932 - 0.616 - 0.0653 = 0.251$

5 0

2 years ago

Lucy has to run two errands. She starts from home and travels 3 miles south to the post office. From the post office, she travel

alexira [117]

Answer:

the correct choice is A. At the gas station

Step-by-step explanation:

Lucy starts at home and travels 3 miles south to the post office. From the post office, she travels 4 miles east to the gas station. As it is known south and east directions form right angle. Since the entire trip forms a triangle, this triangle is right with right angle at the post office.

Call the vertices of this triangle P - post office, G - gas station, H - home. Then HP and PG are legs of this triangle and GH is hypotenuse.

From the given data:

HP=3;

PG=4;

GH=5;

∠P=90°.

The smallest angle is opposite to the smallest side. The smallest side is leg HP, so the smallest angle is G that is the angle at gas station.

6 0

2 years ago

Read 2 more answers

On september 8, 2004, the genesis spacecraft crashed in the utah desert because its parachute did not open. the 210-kg capsule h

maw [93]

311km/h = 86.389 m/s
<span>Initial KE </span>
<span>= 0.5 * 210 * 86.389^2 J </span>

<span>work done by force of ground </span>
<span>= F * 0.81 J </span>

<span>0.5 * 210 * 86.389^2 = 0.81 F </span>

<span>F = 967433.58 N </span>

<span>capsule's weight W= 210 * 9.81 = 2060.1 N </span>

<span>F = 469.6 times capsule weight ---answer</span>

6 0

2 years ago

-3^(-x)-6=-3^x+10<br><br>Solve the equation below for x by graphing plz

vitfil [10]

To graph it, just graph $y=-3^{-x}-6$ and $y=-3^x+10$ and see where they intersect

I would like to solve it by using math and not graphing
if you don't want to see the math, just don't scroll down
the graphical meathod is above, first line, just read it

hmm
multiply both sides by -1
$3^{-x}+6=3^x-10$
multiply both sides by $3^x$
$3^0+6(3^x)=3^{2x}-10(3^x)$
$1+6(3^x)=3^{2x}-10(3^x)$
minus 1 from both sides and minus 6(3^x) from both sides
$0=3^{2x}-16(3^x)-1$
use u subsitution
$u=3^x$
we can rewrite it as
$0=u^2-16u-1$
now factor
I mean use quadratic formula
for $ax^2+bx+c=0$ $x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}$
so for 0=u^2-16u-1, a=1, b=-16, c=-1
$u=\frac{-(-16)+/-\sqrt{(-16)^2-4(1)(-1)}{2(1)}$
$u=8+/-\sqrt{65}$
remember that u=3^x so u>0
if we have u=8+√65, it's fine, but u=8-√65 is negative and not allowed
so therfor
$u=8+\sqrt{65}=3^x$
$8+\sqrt{65}=3^x$
if you take the log base 3 of both sides you get
$log_3(8+\sqrt{65})=x$
if you use ln then
$ln(8+\sqrt{65})=xln(3)$
then
$\frac{ln(8+\sqrt{65})}{ln(3)}=x$

8 0

2 years ago

Read 2 more answers

A volleyball player sets the ball in the air, and the height of the ball after t seconds is given in feet by h= -16^2+12t+6. A t

pychu [463]

Answer:

Step-by-step explanation:

The given function is

$h=-16t^2+12t+6$

The graph of this function is a parabola that opens downwards

The line $h(t)=8$ intersects this parabola, when

$t=0.5,t=0.25$

The teammate can spike the ball after 0.25 seconds or 0.5 seconds.

The two solutions are reasonable. When the volleyball is accelerating into the air, it passes a height of 8 after 0.25 seconds.

When the ball is dropping after it attains maximum height, it attains another height of 8 after 0.5 seconds again.

8 0

2 years ago