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Nikolay [14]
2 years ago
14

The following six students – Andy, Betty, Chris, Frank, Mark and Mary are standing in line outside of a classroom: Chris, the la

st one in line, is right behind Andy; Mark is between Mary and Betty; Frank, who is one ahead of Betty, is the first one in line. Where is Mary in the line? Second Third Fourth Fifth
Mathematics
1 answer:
lorasvet [3.4K]2 years ago
6 0

Answer:

(C) Fourth

Step-by-step explanation:

Taking the restrictions, we place the names on a list.

Chris, the last one in line is right behind Andy

Frank, who is one ahead of Betty, is the first one in line.

Mark is between Mary and Betty

  1. Frank
  2. Betty
  3. Mark
  4. Mary
  5. Andy
  6. Chris
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The number of hours Layla worked each week for the first eight weeks of summer break are recorded below.
Rainbow [258]

Answer: The value of the center increases and the distribution has a smaller spread.

Step-by-step explanation:

Re - arranging the first value in ascending order , we have :

12 ,14, 16 , 19, 21 , 22 , 28 , 32

Median = 19 + 21 / 2

            = 40/2

            = 20

Also calculating the standard variation in order to know the spread , we need to first of all calculate the mean

Mean = 12 + 14 + 16 + 19 + 21 + 22 + 28 + 32  / 8

Mean = 164/8

Mean = 20.5

Therefore to calculate the standard deviation, we need to calculate the variance, which  is

(12-20.5)^{2} +(14-20.5)^{2} + (16-20.5)^{2} + (19-20.5)^{2} + (21-20.5)^{2} + (22-20.5)^{2} + (28-20.5)^{2} + (32-20.5)^{2}  / 8

Variance = 328/8

Variance = 41

Standard deviation = \sqrt{variance}

S.D = \sqrt{41}

S.D = 6.4

Also re arranging the second values , we have :

20 , 24 , 25 , 31

Median = 24 + 25 / 2

Median = 49/2

Median = 24.5

Calculating the S.D using the same format , the S.D = 3.9

Comparing the two we can conclude that the value at the center increases and the distribution has a smaller spread

8 0
2 years ago
Read 2 more answers
Suppose that a Coke/Pepsi survey was conducted of 400 randomly selected individuals from Gainesville. Two hundred people selecte
AlexFokin [52]

Answer:

A. There are not 15 successes and 15 failures. A confidence interval can be computed by adding 2 successes and 2 failures.

6 0
2 years ago
Suppose that 3% of all athletes are using the endurance-enhancing hormone EPO (you should be able to simply compute the percenta
trapecia [35]

Answer:

Step-by-step explanation:

So there is a 3% probability that an athlete is using EPO .

The probability of showing positive on a test when you've used it is 0.99.

3% x 0.99= 2.97%

The probability of a positive result without EPO is 0.1

97% x 0,1 = 9,7 %

My guess is that 2.97% + 9,7% = 12.67% or 0.1267.

I don't know i may be wrong because you've put as an answer 0.0297 but if you like you may take only the first part of the answer.

6 0
2 years ago
A game is played using one die. If the die is rolled and shows 1, the player wins $5. If the die shows any number other than 1,
mash [69]

Answer:

1/5

Step-by-step explanation:

i had a similar question

For each roll you start with paying 2 dollars and you only with 10 dollars one out of 6 rolls (on average). 

So the cost for one play is 2 dollars and your win is 10/6. 

Value is -2+10/6=-1/3 dollars

So you lose 1/3 dollars on average with each game

since you have no limited rolls u put 1/5

this from another question but both same just different numbers

6 0
2 years ago
Show that b^2 is greater than equal to or less than ac, according as a, b, c are in A.P., G.P.
ValentinkaMS [17]

Answer/Step-by-step explanation  (ac > b² or b² < ac. )

A/c to question, we have to show:-

b² >ac in A.P ........ (1)

b² = ac in G.P .....(2)

b² < ac in H.P. ..... (3)

b = a+c/2 (A.P)

b = √ac ( G.P)

b = 2ac/a+c (H.P)

In A.P :

b² > ac = b² - ac

= (a+c/2)² - ac

= (a²+2ac+c²/4) - ac  = a² + 2ac + c² - 4ac / 4

= a² - 2ac + c² / 4  = ( a - c ) ² / 4 > 0  Hence, b²>ac

In G.P:-

b = √ac

Hence, b² = ac

In H.P :-  b² < ac = ac > b²  = ac - b²  = ac - ( 2ac / a+c)

= ac(a+c) - 2ac / a+c

= a²c + ac² - 2ac / a+c

= ac(2ac - 2) / a+c > 0

Hence, ac > b² or b² < ac.

5 0
1 year ago
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