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Gnom [1K]
1 year ago
14

Suppose that some country had an adult population of about 50 million, a labor-force participation rate of 60 percent, and an un

employment rate of 5 percent. How many people were unemployed? a. 1.425 million b. 1.5 million c. 2.5 million d. 5 million
Mathematics
1 answer:
schepotkina [342]1 year ago
8 0

Answer:

The Answer is b. 1.5Million

Step-by-step explanation:

Adult Population = 50 Million

Labor-Force Rate = 60%

Total Labor Force of Adult population = 50Million*60% = 30Million

Unemployment Rate = 5%

People Unemployment =

Total Labor force of Adult population * Unemployment rate

People Unemployment = 30Millon*5%

People Unemployment = 1.5Million

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Given the general identity tan X =sin X/cos X , which equation relating the acute angles, A and C, of a right ∆ABC is true?
irakobra [83]

First, note that m\angle A+m\angle C=90^{\circ}. Then

m\angle A=90^{\circ}-m\angle C \text{ and } m\angle C=90^{\circ}-m\angle A.

Consider all options:

A.

\tan A=\dfrac{\sin A}{\sin C}

By the definition,

\tan A=\dfrac{BC}{AB},\\ \\\sin A=\dfrac{BC}{AC},\\ \\\sin C=\dfrac{AB}{AC}.

Now

\dfrac{\sin A}{\sin C}=\dfrac{\dfrac{BC}{AC}}{\dfrac{AB}{AC}}=\dfrac{BC}{AB}=\tan A.

Option A is true.

B.

\cos A=\dfrac{\tan (90^{\circ}-A)}{\sin (90^{\circ}-C)}.

By the definition,

\cos A=\dfrac{AB}{AC},\\ \\\tan (90^{\circ}-A)=\dfrac{\sin(90^{\circ}-A)}{\cos(90^{\circ}-A)}=\dfrac{\sin C}{\cos C}=\dfrac{\dfrac{AB}{AC}}{\dfrac{BC}{AC}}=\dfrac{AB}{BC},\\ \\\sin (90^{\circ}-C)=\sin A=\dfrac{BC}{AC}.

Then

\dfrac{\tan (90^{\circ}-A)}{\sin (90^{\circ}-C)}=\dfrac{\dfrac{AB}{BC}}{\dfrac{BC}{AC}}=\dfrac{AB\cdot AC}{BC^2}\neq \dfrac{AB}{AC}.

Option B is false.

3.

\sin C = \dfrac{\cos A}{\tan C}.

By the definition,

\sin C=\dfrac{AB}{AC},\\ \\\cos A=\dfrac{AB}{AC},\\ \\\tan C=\dfrac{AB}{BC}.

Now

\dfrac{\cos A}{\tan C}=\dfrac{\dfrac{AB}{AC}}{\dfrac{AB}{BC}}=\dfrac{BC}{AC}\neq \sin C.

Option C is false.

D.

\cos A=\tan C.

By the definition,

\cos A=\dfrac{AB}{AC},\\ \\\tan C=\dfrac{AB}{BC}.

As you can see \cos A\neq \tan C and option D is not true.

E.

\sin C = \dfrac{\cos(90^{\circ}-C)}{\tan A}.

By the definition,

\sin C=\dfrac{AB}{AC},\\ \\\cos (90^{\circ}-C)=\cos A=\dfrac{AB}{AC},\\ \\\tan A=\dfrac{BC}{AB}.

Then

\dfrac{\cos(90^{\circ}-C)}{\tan A}=\dfrac{\dfrac{AB}{AC}}{\dfrac{BC}{AB}}=\dfrac{AB^2}{AC\cdot BC}\neq \sin C.

This option is false.

8 0
2 years ago
Read 2 more answers
nikki backyard is in the shape of a rectangle. the length is 27 feet. The width is one-third the length plus 4 feet. write and e
PIT_PIT [208]

Answer:

A= Length x Width

A= 27 x (1/3 x 27 + 4)

A=27 x (9 + 4)

A= 27 x 13

A= 351

Step-by-step explanation:

ye

4 0
1 year ago
The heights of the trees for sale at two nurseries are shown below. Heights of trees at Yard Works in feet : 7, 9, 7, 12, 5 Heig
Troyanec [42]

Answer:

The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.

Step-by-step explanation:

1). Height of the trees at Yard Works are = 7,9,7,12,5 feet

So mean height of the trees = (7+9+7+12+5)÷5

                                               = 40÷5 =8 feet

Standard deviation of the trees at Yard works = ∑(║(height of the tree-mean height of the tree))║/(number of trees)

(height of the tree-mean height of the tree)= ║(7-8)║+║(9-8)║+║(7-8)║+║(12-8)║+║(5-8)║ = (1)+1+(1)+4+(3)= 10

Therefore standard deviation = (10)/(5) =2

2). In the same way mean height of the trees at Grow Station=(9+11+6+12+7)/5= 45/5 = 9

Now we will calculate the mean deviation of the tress at Grow Station

= ∑║(height of the tree-mean height of the tree)║/(number of trees)

= ║(9-9)║+║(11-9)║+║(6-9)║+║(12-9)║+║(7-9)║/(5)

= (0+2+3+3+2)/5

= 10/5 =2

Therefore The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.

                                                             

7 0
2 years ago
Read 2 more answers
Sharon and Jacob started at the same place. Jacob walked 3 m north and then 4 m west. Sharon walked 5 m south and 12 m east. How
Ilya [14]

Consider the coordinate plane:

1. The origin is the point where Sharon and Jacob started - (0,0).

2. North - positive y-direction, south - negetive y-direction.

3. East - positive x-direction, west - negative x-direction.

Then,

  • if Jacob walked 3 m north and then 4 m west, the point where he is now has coordinates (-4,3);
  • if Sharon walked 5 m south and 12 m east, the point where she is now has coordinates (12,-5).

The distance between two points with coordinates (x_1,y_1) and (x_2,y_2) can be calculated using formula

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}.

Therefore, the distance between  Jacob and Sharon is

D=\sqrt{(12-(-4))^2+(-5-3)^2}=\sqrt{16^2+8^2}=\sqrt{256+64}=\sqrt{320}=8\sqrt{5}\approx 11.18\ m.

7 0
2 years ago
Express 3.222......in p/q form​
beks73 [17]

Answer:

3.22222......  = \frac{29}{9}

Step-by-step explanation:

In this question we have to convert the number given in recurrent decimals into fraction.

Recurrent decimal number is 3.22222.......

Let x = 3.2222.........   -------(1)

Multiply this expression by 10.

10x = 32.2222........... -------(2)

Now subtract the expression (1) from (2),

10x = 32.22222.....

<u>    x = 3.22222.......</u>

9x = 29

x = \frac{29}{9}

Therefore, recurrent decimal number can be written as \frac{29}{9} which is in the form of \frac{p}{q}.

6 0
2 years ago
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