Answer:
<h2>The answer is 0.23(approx).</h2>
Step-by-step explanation:
The given die is a three sided die, hence, there are only three possibilities of getting the outcomes.
We need to find the probability of getting exactly 3s as the result.
From the sequence of 6 independent rolls, 2 rolls can be chosen in 
ways.
The probability of getting two 3 as outcome is 
.
In the rest of the 4 sequences, will not be any 3 as outcome.
Probability of not getting a outcome rather than 3 is 
.
Hence, the required probability is 
≅0.2966 or, 0.23.
If she picks the letter A, she can then pick either 1 , 2 or 3
If she picks B, she can pick 1, 2, or 3 and so on.
See attached picture for the sample space :
In Δ ABC, ∠A=120°, AB=AC=1
To draw a circumscribed circle Draw perpendicular bisectors of any of two sides.The point where these bisectors meet is the center of the circle.Mark the center as O.
Then join OA, OB, and OC.
Taking any one OA,OB and OC as radius draw the circumcircle.
Now, from O Draw OM⊥AB and ON⊥AC.
As chord AB and AC are equal,So OM and ON will also be equal.
The reason being that equal chords are equidistant from the center.
AM=MB=1/2 and AN=NC=1/2 [ perpendicular from the center to the chord bisects the chord.]
In Δ OMA and ΔONA
OM=ON [proved above]
OA is common.
MA=NA=1/2 [proved above]
ΔOMA≅ ONA [SSS]
∴ ∠OAN =∠OAM=60° [ CPCT]
In Δ OAN
OA=1
∴ OA=OB=OC=1, which is the radius of given Circumscribed circle.
By completing the experiment a few more times and combining the results to the trails already done
