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Goryan [66]
2 years ago
7

There are three letter tiles—A, B, and C—in a bag; and there are three number tiles—1, 2, and 3—in another bag. Alexis picks a l

etter tile, and then she picks a number tile. Complete the table representing the sample space for this situation.

Mathematics
1 answer:
sdas [7]2 years ago
5 0
If she picks the letter A, she can then pick either 1 , 2 or 3
If she picks B, she can pick 1, 2, or 3 and so on.

 See attached picture for the sample space :

You might be interested in
4C. Quintin is using the three different shaped
Sauron [17]

The smallest number of tiles Quintin will need in order to tile  his floor is 20

The given parameters;

  • number of different shapes of tiles available = 3
  • number of each shape = 5
  • area of each square shape tiles, A = 2000 cm²
  • length of the floor, L = 10 m = 1000 cm
  • width of the floor, W = 6 m = 600 cm

To find:

  • the smallest number of tiles Quintin will need in order to tile his floor

Among the three different shapes available, total area of one is calculated as;

A_{one \ square \ type} = 5 \times 2000 \ cm^2 = 10,000 \ cm^2

Area of the floor is calculated as;

A_{floor} = 1000 \ cm \times 600 \ cm = 600,000 \ cm^2

The maximum number tiles needed (this will be possible if only one shape type is used)

maximum \ number= \frac{Area \ of \ floor}{total \ area \ of \ one \ shape \ type} \\\\maximum \ number= \frac{600,000 \ cm^2}{10,000 \ cm^2} \\\\maximum \ number=  60

When all the three different shape types are used we can get the smallest number of tiles needed.

The minimum or smallest number of tiles needed (this will be possible if all the 3 different shapes are used)

3 \times \ smallest \ number  = 60\\\\smallest \ number = \frac{60}{3} \\\\smallest \ number = 20

Thus, the smallest number of tiles Quintin will need in order to tile  his floor is 20

Learn more here: brainly.com/question/13877427

3 0
2 years ago
Mr. Schwartz builds toy cars. He begins the week with a supply of 85 wheels, and uses 4 wheels for each car he builds. Mr. Schwa
Reptile [31]

When will he have less than 40 wheels left? Well you can make the equation...

85-4x=40

And then solve for x.

85-4x=40

-4x=-45

x=11 1/4 rounded up to 12

answer: He will have less than 40 wheels left after he has built 12 cars.

5 0
2 years ago
A new technology for the production of integrated circuits is being mastered. The technology will be rejected if the percentage
max2010maxim [7]

Answer:

5901

Step-by-step explanation:

The margin of error is the critical value times the standard error.

ME = CV × SE

For α = 0.05, the critical value is z = 1.96.

The standard error of a proportion is √(pq/n).  Given p = 0.04, then q = 1−p = 0.96.

The margin of error is 0.5% or 0.005.

Plugging in:

0.005 = 1.96 √(0.04 × 0.96 / n)

n ≈ 5901

8 0
2 years ago
In a study on the fertility of married women conducted by Martin O’Connell and Carolyn C. Rogers for the Census Bureau in 1979,
Fed [463]

Answer:

we cannot conclude hat the proportion of wives married less than two years who planned to have children is significantly higher than the proportion of wives married five years

Step-by-step explanation:

Given that in a study on the fertility of married women conducted by Martin O’Connell and Carolyn C. Rogers for the Census Bureau in 1979, two groups of childless wives aged 25 to 29 were selected at random, and each was asked if she eventually planned to have a child. One group was selected from among wives married less than two years and the other from among wives married five years.

Let X be the group married less than 2 years and Y less than 5 years

                         X        Y     Total

Sample size   300   300    600

Favouring       240   288    528

p                      0.8     0.96  0.88

H_0: p_x=p_y\\H_a: p_x>p_y

p difference = -0.16

Std error for difference = \sqrt{0.88*0.12/600} =0.01327

Test statistic = p difference/std error=-6.03

p value <0.000001

Since p is less than alpha 0.05 we cannot conclude hat the proportion of wives married less than two years who planned to have children is significantly higher than the proportion of wives married five years

4 0
2 years ago
A class with n kids lines up for recess. The order in which the kids line up is random with eachordering being equally likely. T
Elis [28]

Answer:

A) P(Betty is first in line and mary is last) = P(B₁) + P(Mₙ) - (P(B₁) × P(Mₙ/B₁))

B) The method used is Relative frequency approach.

Step-by-step explanation:

From the question, we are told a sample of n kids line up for recess.

Now, the order in which they line up is random with each ordering being equally likely. Thus, this means that the probability of each kid to take a position is n(total of kids/positions).

Since we are being asked about 3 kids from the class, let's assign a letter to each kid:

J: John

B: Betty

M: Mary

A) Now, we want to find the probability that Betty is first in line or Mary is last in line.

In this case, the events are not mutually exclusive, since it's possible that "Betty is first but Mary is not last" or "Mary is last but Betty is not first" or "Betty is the first in line and Mary is last". Thus, there is an intersection between them and the probability is symbolized as;

P(B₁ ∪ Mₙ) = P(B₁) + P (Mₙ) - P(B₁ ∩ Mₙ) = P(B₁) + P(Mₙ) - (P(B₁) × P(Mₙ/B₁))

Where;

The suffix 1 refers to the first position while the suffix n refers to the last position.

Also, P(B₁ ∩ Mₙ) = P(B₁) × P(Mₙ/B₁)

This is because the events "Betty" and "Mary" are not independent since every time a kid takes his place the probability of the next one is affected.

B) The method used is Relative frequency approach.

In this method, the probabilities are usually assigned on the basis of experimentation or historical data.

For example, If A is an event we are considering, and we assume that we have performed the same experiment n times so that n is the number of times A could have occurred.

Also, let n_A be the number of times that A did occur.

Now, the relative frequency would be written as (n_A)/n.

Thus, in this method, we will define P(A) as:

P(A) = lim:n→∞[(n_A)/n]

7 0
2 years ago
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