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ra1l [238]
2 years ago
14

point M with coordinates (3,4) is the midpoint of the line AB and A has the point (-1,6). what is the point of B?

Mathematics
1 answer:
irina [24]2 years ago
4 0

Answer:

  B = (7, 2)

Step-by-step explanation:

B = 2M -A

B = 2(3, 4) -(-1, 6) = (2·3-(-1), 2·4-6)

B = (7, 2)

_____

The expression for the other end point, B, comes from the equation for the midpoint.

  M = (A +B)/2

  2M = A + B . . . . . multiply by 2

  2M -A = B . . . . . . subtract A to get an expression for B

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If m< LMP is 11 degrees more than m< NMP and m< NML =137, find each measure
Agata [3.3K]

First, note that for angles LMP and NMP you have

m\angle LMP+m\angle NMP=m\angle NML.

If m\angle LMP is 11^{\circ} more than m\angle MNP, then

m\angle LMP=m\angle NMP+11^{\circ}.

Now, since m\angle MNL=137^{\circ}, you have

137^{\circ}=m\angle NMP+11^{\circ}+m\angle NMP,\\ \\2m\angle NMP=137^{\circ}-11^{\circ}=126^{\circ},\\ \\m\angle NMP=63^{\circ}.

Therefore,

m\angle LMP=63^{\circ}+11^{\circ}=74^{\circ}.

Answer: m\angle LMP=74^{\circ},\ m\angle NMP=63^{\circ}.


7 0
2 years ago
A blimp is 1500 meters high in the air and measures the angles of depression to two stadiums to the west of the blimp. If those
grigory [225]
Let stadium 1 be the one on the left and stadium 2 the one on the right.

Angle above stadium 1 is 72.9° and the angle above stadium 2 is 34.1° using the angle property of alternate angles(because both the ground and the dotted line are parallel).

For the next part we need to use the trigonometric function of tangent.

As tan x = opposite / adjacent,
Tan 72.9°=1500/ adjacent ( the ground from O to stadium 1)

Therefore the adjacent is 1500/tan 72.9°= 461.46 m( to 5 s.f.)

Same for the next angle,
Tan 34.1°=1500/ adjacent ( the ground from O to stadium 2)

Therefore, the adjacent is 1500/tan 34.1° = 2215.49 m (to 5 s.f.)

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2 years ago
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Answer:

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Step-by-step explanation:

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2 years ago
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2 years ago
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mr Goodwill [35]
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Work Shown:

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5 0
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