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maxonik [38]
1 year ago
15

Miguel's irrigation tank for his large garden held 45.5 gallons before he began to fill it at a rate of 17 gallons per minute. B

efore he started watering the plants in his garden, Miguel's friend Alejandro checked his irrigation tank and found it contained 425 gallons. If Alejandro is irrigating his plants at rate of 11.5 gallons per minute, how much water will be in each tank when both tanks have the same amount of water?
Mathematics
1 answer:
egoroff_w [7]1 year ago
6 0

Answer:

Step-by-step explanation:

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What equation can be used to solve for angle C?
matrenka [14]

The formula for calculating the total interior angle in a regular polygon is given as:

total interior angle = (n -2) 180

where n is the number of sides and since there are  sides:

total interior angle = 360°

To get this angle, we know that it is the summation of all angles:

360° = angle A + angle C + angle B + angle D                         ---> 1

Looking closely, we can see that segments BC and AD are parallel which means that:

angle A + angle C = angle B + angle D                                       ---> 2

Substituting equation 2 to 1:

360 = 2 (angle A + angle C)

angle A + angle C = 180

(x + 16) + (6x – 4) = 180 

 

Answer:

B

6 0
2 years ago
Use the converse of the side-splitter theorem to determine if T R is parallel to R S. Which statement is true? Line segment TU i
kramer

Answer:

IM SORRY              MI IM

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Express f(x) = |x-2| +|x+2| in the non-modulus form. Hence, sketch the graph of f.
alexgriva [62]
Recall that

|x|=\begin{cases}x&\text{if }x\ge0\\-x&\text{if }x

There are three cases to consider:

(1) When x+2, we have |x+2|=-(x+2) and |x-2|=-(x-2), so

|x-2|+|x+2|=-(x-2)-(x+2)=-2x-4

(2) When x+2\ge0 and x-2, we get |x+2|=x+2 and |x-2|=-(x-2), so

|x-2|+|x+2|=-(x-2)+(x+2)=4

(3) When x-2\ge0, we have |x+2|=x+2 and |x-2|=x-2, so

|x-2|+|x+2|=(x-2)+(x+2)=2x

So

|x-2|+|x+2|=\begin{cases}-2x-4&\text{if }x
4 0
1 year ago
Choose the abbreviation of the postulate or theorem that supports the conclusion that △WAS ≅ △NOT.
Nana76 [90]

Answer: SSS

<u>Step-by-step explanation:</u>

<u>W</u>A = <u>N</u>O

<u>A</u>S = <u>O</u>T

<u>S</u>W = <u>T</u>N

△WAS ≅ △NOT by SSS Congruency Theorem

5 0
2 years ago
Read 2 more answers
How many solutions does the equation sin(5x) = 1/2 have on the interval (0, 2PI]
Darina [25.2K]

Answer:

Step-by-step explanation:

Given the equation

Sin(5x) = ½

5x = arcSin(½)

5x = 30°

Then,

The general formula for sin is

5θ = n180 + (-1)ⁿθ

Divide through by 5

θ = n•36 + (-1)ⁿ30/5

θ = 36n + (-1)ⁿ6

The range of the solution is

0<θ<2π I.e 0<θ<360

First solution

When n = 0

θ = 36n + (-1)ⁿθ

θ = 0×36 + (-1)^0×6

θ = 6°

When n = 1

θ = 36n + (-1)ⁿ6

θ = 36-6

θ = 30°

When n = 2

θ = 36n + (-1)ⁿ6

θ = 36×2 + 6

θ = 78°

When n =3

θ = 36n + (-1)ⁿ6

θ = 36×3 - 6

θ = 102°

When n=4

θ = 36n + (-1)ⁿ6

θ = 36×4 + 6

θ = 150

When n =5

θ = 36n + (-1)ⁿ6

θ = 36×5 - 6

θ = 174°

When n = 6

θ = 36n+ (-1)ⁿ6

θ = 36×6 + 6

θ = 222°

When n = 7

θ = 36n + (-1)ⁿ6

θ = 36×7 - 6

θ = 246°

When n =8

θ = 36n + (-1)ⁿ6

θ = 36×8 + 6

θ = 294°

When n =9

θ = 36n + (-1)ⁿ6

θ = 36×9 - 6

θ = 318°

When n =10

θ = 36n + (-1)ⁿ6

θ = 36×10 + 6

θ = 366°

When n = 10 is out of range of θ

Then, the solution is from n =0 to n=9

So the equation have 10 solutions in the range 0<θ<2π

4 0
1 year ago
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